Graph y+2=1/5*(x-1)

$y + 2 = \frac{1}{5} \cdot (x - 1)$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$y = \frac{x}{5} - \frac{1}{5} - 2$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$y = \frac{x}{5} - \frac{1}{5} - 2 \cdot \frac{5}{5}$

Combine $- 2$ and $\frac{5}{5}$ .

$y = \frac{x}{5} - \frac{1}{5} + \frac{- 2 \cdot 5}{5}$

Combine the numerators over the common denominator.

$y = \frac{x}{5} + \frac{- 1 - 2 \cdot 5}{5}$

Simplify the numerator.

Multiply $- 2$ by $5$ .

$y = \frac{x}{5} + \frac{- 1 - 10}{5}$

Subtract $10$ from $- 1$ .

$y = \frac{x}{5} + \frac{- 11}{5}$

Move the negative in front of the fraction.

$y = \frac{x}{5} - \frac{11}{5}$

Step 2

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder terms.

$y = \frac{1}{5} x - \frac{11}{5}$

Step 3

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{5}$

$b = - \frac{11}{5}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{5}$

y-intercept: $(0, - \frac{11}{5})$

Slope: $\frac{1}{5}$

y-intercept: $(0, - \frac{11}{5})$

Step 4

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder terms.

$y = \frac{1}{5} x - \frac{11}{5}$

Find the x-intercept.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{1}{5} x - \frac{11}{5}$

Solve the equation.

Rewrite the equation as $\frac{1}{5} x - \frac{11}{5} = 0$ .

$\frac{1}{5} x - \frac{11}{5} = 0$

Combine $\frac{1}{5}$ and $x$ .

$\frac{x}{5} - \frac{11}{5} = 0$

Add $\frac{11}{5}$ to both sides of the equation.

$\frac{x}{5} = \frac{11}{5}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$x = 11$

x-intercept(s) in point form.

x-intercept(s): $(11, 0)$

Find the y-intercept.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{1}{5} \cdot (0) - \frac{11}{5}$

Solve the equation.

Multiply $\frac{1}{5}$ by $0$ .

$y = \frac{1}{5} \cdot 0 - \frac{11}{5}$

Remove parentheses.

$y = \frac{1}{5} \cdot (0) - \frac{11}{5}$

Simplify $\frac{1}{5} \cdot (0) - \frac{11}{5}$ .

Multiply $\frac{1}{5}$ by $0$ .

$y = 0 - \frac{11}{5}$

Subtract $\frac{11}{5}$ from $0$ .

$y = - \frac{11}{5}$

y-intercept(s) in point form.

y-intercept(s): $(0, - \frac{11}{5})$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & - \frac{11}{5} \\ 11 & 0 \end{array}$

Step 5

Graph the line using the slope and the y-intercept, or the points.

Slope: $\frac{1}{5}$

y-intercept: $(0, - \frac{11}{5})$

$\begin{array}{c} x & y \\ 0 & - \frac{11}{5} \\ 11 & 0 \end{array}$

Step 6

Graph y+2=1/5*(x-1)

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