Graph (y^2)/16-(x^2)/4=1

$\frac{y^{2}}{16} - \frac{x^{2}}{4} = 1$

Step 1

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{y^{2}}{16} - \frac{x^{2}}{4} = 1$

Step 2

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

$\frac{{(y - k)}^{2}}{a^{2}} - \frac{{(x - h)}^{2}}{b^{2}} = 1$

Step 3

Match the values in this hyperbola to those of the standard form. The variable $h$ represents the x-offset from the origin, $k$ represents the y-offset from origin, $a$ .

$a = 4$

$b = 2$

$k = 0$

$h = 0$

Step 4

The center of a hyperbola follows the form of $(h, k)$ . Substitute in the values of $h$ and $k$ .

$(0, 0)$

Step 5

Find $c$ , the distance from the center to a focus.

Find the distance from the center to a focus of the hyperbola by using the following formula.

$\sqrt{a^{2} + b^{2}}$

Substitute the values of $a$ and $b$ in the formula.

$\sqrt{{(4)}^{2} + {(2)}^{2}}$

Simplify.

Raise $4$ to the power of $2$ .

$\sqrt{16 + {(2)}^{2}}$

Raise $2$ to the power of $2$ .

$\sqrt{16 + 4}$

Add $16$ and $4$ .

$\sqrt{20}$

Rewrite $20$ as $2^{2} \cdot 5$ .

Factor $4$ out of $20$ .

$\sqrt{4 (5)}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 5}$

Pull terms out from under the radical.

$2 \sqrt{5}$

Step 6

Find the vertices.

The first vertex of a hyperbola can be found by adding $a$ to $k$ .

$(h, k + a)$

Substitute the known values of $h$ , $a$ , and $k$ into the formula and simplify.

$(0, 4)$

The second vertex of a hyperbola can be found by subtracting $a$ from $k$ .

$(h, k - a)$

Substitute the known values of $h$ , $a$ , and $k$ into the formula and simplify.

$(0, - 4)$

The vertices of a hyperbola follow the form of $(h, k \pm a)$ . Hyperbolas have two vertices.

$(0, 4), (0, - 4)$

Step 7

Find the foci.

The first focus of a hyperbola can be found by adding $c$ to $k$ .

$(h, k + c)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(0, 2 \sqrt{5})$

The second focus of a hyperbola can be found by subtracting $c$ from $k$ .

$(h, k - c)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(0, - 2 \sqrt{5})$

The foci of a hyperbola follow the form of $(h, k \pm \sqrt{a^{2} + b^{2}})$ . Hyperbolas have two foci.

$(0, 2 \sqrt{5}), (0, - 2 \sqrt{5})$

Step 8

Find the eccentricity.

Find the eccentricity by using the following formula.

$\frac{\sqrt{a^{2} + b^{2}}}{a}$

Substitute the values of $a$ and $b$ into the formula.

$\frac{\sqrt{{(4)}^{2} + {(2)}^{2}}}{4}$

Simplify.

Simplify the numerator.

Raise $4$ to the power of $2$ .

$\frac{\sqrt{16 + 2^{2}}}{4}$

Raise $2$ to the power of $2$ .

$\frac{\sqrt{16 + 4}}{4}$

Add $16$ and $4$ .

$\frac{\sqrt{20}}{4}$

Rewrite $20$ as $2^{2} \cdot 5$ .

Factor $4$ out of $20$ .

$\frac{\sqrt{4 (5)}}{4}$

Rewrite $4$ as $2^{2}$ .

$\frac{\sqrt{2^{2} \cdot 5}}{4}$

Pull terms out from under the radical.

$\frac{2 \sqrt{5}}{4}$

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 \sqrt{5}$ .

$\frac{2 (\sqrt{5})}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$\frac{2 \sqrt{5}}{2 \cdot 2}$

Cancel the common factor.

$\frac{2 \sqrt{5}}{2 \cdot 2}$

Rewrite the expression.

$\frac{\sqrt{5}}{2}$

Step 9

Find the focal parameter.

Find the value of the focal parameter of the hyperbola by using the following formula.

$\frac{b^{2}}{\sqrt{a^{2} + b^{2}}}$

Substitute the values of $b$ and $\sqrt{a^{2} + b^{2}}$ in the formula.

$\frac{2^{2}}{2 \sqrt{5}}$

Simplify.

Cancel the common factor of $2^{2}$ and $2$ .

Factor $2$ out of $2^{2}$ .

$\frac{2 \cdot 2}{2 \sqrt{5}}$

Cancel the common factors.

Factor $2$ out of $2 \sqrt{5}$ .

$\frac{2 \cdot 2}{2 (\sqrt{5})}$

Cancel the common factor.

$\frac{2 \cdot 2}{2 \sqrt{5}}$

Rewrite the expression.

$\frac{2}{\sqrt{5}}$

Multiply $\frac{2}{\sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\frac{2}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}$

Combine and simplify the denominator.

Multiply $\frac{2}{\sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\frac{2 \sqrt{5}}{\sqrt{5} \sqrt{5}}$

Raise $\sqrt{5}$ to the power of $1$ .

$\frac{2 \sqrt{5}}{{\sqrt{5}}^{1} \sqrt{5}}$

Raise $\sqrt{5}$ to the power of $1$ .

$\frac{2 \sqrt{5}}{{\sqrt{5}}^{1} {\sqrt{5}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \sqrt{5}}{{\sqrt{5}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{2 \sqrt{5}}{{\sqrt{5}}^{2}}$

Rewrite ${\sqrt{5}}^{2}$ as $5$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5}$ as $5^{\frac{1}{2}}$ .

$\frac{2 \sqrt{5}}{{(5^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \sqrt{5}}{5^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \sqrt{5}}{5^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{5}}{5^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{2 \sqrt{5}}{5^{1}}$

Evaluate the exponent.

$\frac{2 \sqrt{5}}{5}$

Step 10

The asymptotes follow the form $y = \pm \frac{a (x - h)}{b} + k$ because this hyperbola opens up and down.

$y = \pm 2 \cdot x + 0$

Step 11

Add $2 \cdot x$ and $0$ .

$y = 2 x$

Step 12

Add $- 2 \cdot x$ and $0$ .

$y = - 2 x$

Step 13

This hyperbola has two asymptotes.

$y = 2 x, y = - 2 x$

Step 14

These values represent the important values for graphing and analyzing a hyperbola.

Center: $(0, 0)$

Vertices: $(0, 4), (0, - 4)$

Foci: $(0, 2 \sqrt{5}), (0, - 2 \sqrt{5})$

Eccentricity: $\frac{\sqrt{5}}{2}$

Focal Parameter: $\frac{2 \sqrt{5}}{5}$

Asymptotes: $y = 2 x$ , $y = - 2 x$

Step 15

Graph (y^2)/16-(x^2)/4=1

Related Questions

Support LCMGCF.com by disabling your adblocker.