Graph y^2+x+10=0

$y^{2} + x + 10 = 0$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $y^{2}$ from both sides of the equation.

$x + 10 = - y^{2}$

Subtract $10$ from both sides of the equation.

$x = - y^{2} - 10$

Step 2

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $- y^{2} - 10$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = 0$

$c = - 10$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 \cdot - 1}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 \cdot - 1}$

Move the negative one from the denominator of $\frac{0}{- 1}$ .

$d = - 1 \cdot 0$

Rewrite $- 1 \cdot 0$ as $- 0$ .

$d = - 0$

Multiply $- 1$ by $0$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 10 - \frac{0^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = - 10 - \frac{0}{4 \cdot - 1}$

Multiply $4$ by $- 1$ .

$e = - 10 - \frac{0}{- 4}$

Divide $0$ by $- 4$ .

$e = - 10 - 0$

Multiply $- 1$ by $0$ .

$e = - 10 + 0$

Add $- 10$ and $0$ .

$e = - 10$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(y + 0)}^{2} - 10$ .

$- {(y + 0)}^{2} - 10$

Set $x$ equal to the new right side.

$x = - {(y + 0)}^{2} - 10$

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = - 10$

$k = 0$

Since the value of $a$ is negative, the parabola opens left.

Opens Left

Find the vertex $(h, k)$ .

$(- 10, 0)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 1}$

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1)}{4 \cdot - 1}$

Move the negative in front of the fraction.

$- \frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the x-coordinate $h$ if the parabola opens left or right.

$(h + p, k)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- \frac{41}{4}, 0)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$y = 0$

Find the directrix.

The directrix of a parabola is the vertical line found by subtracting $p$ from the x-coordinate $h$ of the vertex if the parabola opens left or right.

$x = h - p$

Substitute the known values of $p$ and $h$ into the formula and simplify.

$x = - \frac{39}{4}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Left

Vertex: $(- 10, 0)$

Focus: $(- \frac{41}{4}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{39}{4}$

Direction: Opens Left

Vertex: $(- 10, 0)$

Focus: $(- \frac{41}{4}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{39}{4}$

Step 3

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Substitute the $x$ value $- 12$ into $f (x) = \sqrt{- x - 10}$ . In this case, the point is $(- 12, 1.41421356)$ .

Replace the variable $x$ with $- 12$ in the expression.

$f (- 12) = \sqrt{- (- 12) - 10}$

Simplify the result.

Multiply $- 1$ by $- 12$ .

$f (- 12) = \sqrt{12 - 10}$

Subtract $10$ from $12$ .

$f (- 12) = \sqrt{2}$

The final answer is $\sqrt{2}$ .

$y = \sqrt{2}$

Convert $\sqrt{2}$ to decimal.

$= 1.41421356$

Substitute the $x$ value $- 12$ into $f (x) = - \sqrt{- x - 10}$ . In this case, the point is $(- 12, - 1.41421356)$ .

Replace the variable $x$ with $- 12$ in the expression.

$f (- 12) = - \sqrt{- (- 12) - 10}$

Simplify the result.

Multiply $- 1$ by $- 12$ .

$f (- 12) = - \sqrt{12 - 10}$

Subtract $10$ from $12$ .

$f (- 12) = - \sqrt{2}$

The final answer is $- \sqrt{2}$ .

$y = - \sqrt{2}$

Convert $- \sqrt{2}$ to decimal.

$= - 1.41421356$

Substitute the $x$ value $- 11$ into $f (x) = \sqrt{- x - 10}$ . In this case, the point is $(- 11, 1)$ .

Replace the variable $x$ with $- 11$ in the expression.

$f (- 11) = \sqrt{- (- 11) - 10}$

Simplify the result.

Multiply $- 1$ by $- 11$ .

$f (- 11) = \sqrt{11 - 10}$

Subtract $10$ from $11$ .

$f (- 11) = \sqrt{1}$

Any root of $1$ is $1$ .

$f (- 11) = 1$

The final answer is $1$ .

$y = 1$

Convert $1$ to decimal.

$= 1$

Substitute the $x$ value $- 11$ into $f (x) = - \sqrt{- x - 10}$ . In this case, the point is $(- 11, - 1)$ .

Replace the variable $x$ with $- 11$ in the expression.

$f (- 11) = - \sqrt{- (- 11) - 10}$

Simplify the result.

Multiply $- 1$ by $- 11$ .

$f (- 11) = - \sqrt{11 - 10}$

Subtract $10$ from $11$ .

$f (- 11) = - \sqrt{1}$

Any root of $1$ is $1$ .

$f (- 11) = - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$f (- 11) = - 1$

The final answer is $- 1$ .

$y = - 1$

Convert $- 1$ to decimal.

$= - 1$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 12 & 1.41 \\ - 12 & - 1.41 \\ - 11 & 1 \\ - 11 & - 1 \\ - 10 & 0 \end{array}$

Step 4

Graph the parabola using its properties and the selected points.

Direction: Opens Left

Vertex: $(- 10, 0)$

Focus: $(- \frac{41}{4}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{39}{4}$

$\begin{array}{c} x & y \\ - 12 & 1.41 \\ - 12 & - 1.41 \\ - 11 & 1 \\ - 11 & - 1 \\ - 10 & 0 \end{array}$

Step 5

Graph y^2+x+10=0

Related Questions

Support LCMGCF.com by disabling your adblocker.