Graph y<=-2x^2+10x-8

$y \leq - 2 x^{2} + 10 x - 8$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- 2 x^{2} + 10 x - 8$ .

$y \leq - 2 x^{2} + 10 x - 8$