Graph y<=2x+3 3x+y<=-2

$y \leq 2 x + 3$ $3 x + y \leq - 2$

Graph $y \leq 2 x + 3$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, 3)$

Slope: $2$

y-intercept: $(0, 3)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $2 x + 3$ .

$y \leq 2 x + 3$

Graph $3 x + y \leq - 2$ .

Write in $y = m x + b$ form.

Subtract $3 x$ from both sides of the inequality.

$y \leq - 2 - 3 x$

Rearrange terms.

$y \leq - 3 x - 2$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 3$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 3$

y-intercept: $(0, - 2)$

Slope: $- 3$

y-intercept: $(0, - 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- 3 x - 2$ .

$y \leq - 3 x - 2$

Plot each graph on the same coordinate system.

$y \leq 2 x + 3$

$3 x + y \leq - 2$