Graph y>=-2x+5 y<=-x^2-x+4

$y \geq - 2 x + 5$ $y \leq - x^{2} - x + 4$

Graph $y \geq - 2 x + 5$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 2$

$b = 5$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 2$

y-intercept: $(0, 5)$

Slope: $- 2$

y-intercept: $(0, 5)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- 2 x + 5$ .

$y \geq - 2 x + 5$

Graph $y \leq - x^{2} - x + 4$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- x^{2} - x + 4$ .

$y \leq - x^{2} - x + 4$

Plot each graph on the same coordinate system.

$y \geq - 2 x + 5$

$y \leq - x^{2} - x + 4$