Graph y=3-1/2 square root of 6-x

$y = 3 - \frac{1}{2} \sqrt{6 - x}$

Find the domain for $y = 3 - \frac{1}{2} \cdot \sqrt{6 - x}$ so that a list of $x$ values can be picked to find a list of points, which will help graphing the radical.

Set the radicand in $\sqrt{6 - x}$ greater than or equal to $0$ to find where the expression is defined.

$6 - x \geq 0$

Solve for $x$ .

Subtract $6$ from both sides of the inequality.

$- x \geq - 6$

Divide each term in $- x \geq - 6$ by $- 1$ and simplify.

Divide each term in $- x \geq - 6$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \leq \frac{- 6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} \leq \frac{- 6}{- 1}$

Divide $x$ by $1$ .

$x \leq \frac{- 6}{- 1}$

Simplify the right side.

Divide $- 6$ by $- 1$ .

$x \leq 6$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 6]$

Set-Builder Notation:

${x | x \leq 6}$

Interval Notation:

$(- \infty, 6]$

Set-Builder Notation:

${x | x \leq 6}$

To find the radical expression end point, substitute the $x$ value $6$ , which is the least value in the domain, into $f (x) = \frac{6 - \sqrt{6 - x}}{2}$ .

Replace the variable $x$ with $6$ in the expression.

$f (6) = \frac{6 - \sqrt{6 - (6)}}{2}$

Simplify the result.

Simplify the numerator.

Multiply $- 1$ by $6$ .

$f (6) = \frac{6 - \sqrt{6 - 6}}{2}$

Subtract $6$ from $6$ .

$f (6) = \frac{6 - \sqrt{0}}{2}$

Rewrite $0$ as $0^{2}$ .

$f (6) = \frac{6 - \sqrt{0^{2}}}{2}$

Pull terms out from under the radical, assuming positive real numbers.

$f (6) = \frac{6 - 0}{2}$

Multiply $- 1$ by $0$ .

$f (6) = \frac{6 + 0}{2}$

Add $6$ and $0$ .

$f (6) = \frac{6}{2}$

Divide $6$ by $2$ .

$f (6) = 3$

The final answer is $3$ .

$3$

The radical expression end point is $(6, 3)$ .

$(6, 3)$

Select a few $x$ values from the domain. It would be more useful to select the values so that they are next to the $x$ value of the radical expression end point.

Substitute the $x$ value $4$ into $f (x) = \frac{6 - \sqrt{6 - x}}{2}$ . In this case, the point is $(4, \frac{6 - \sqrt{2}}{2})$ .

Replace the variable $x$ with $4$ in the expression.

$f (4) = \frac{6 - \sqrt{6 - (4)}}{2}$

Simplify the result.

Simplify the numerator.

Multiply $- 1$ by $4$ .

$f (4) = \frac{6 - \sqrt{6 - 4}}{2}$

Subtract $4$ from $6$ .

$f (4) = \frac{6 - \sqrt{2}}{2}$

The final answer is $\frac{6 - \sqrt{2}}{2}$ .

$y = \frac{6 - \sqrt{2}}{2}$

Substitute the $x$ value $5$ into $f (x) = \frac{6 - \sqrt{6 - x}}{2}$ . In this case, the point is $(5, \frac{5}{2})$ .

Replace the variable $x$ with $5$ in the expression.

$f (5) = \frac{6 - \sqrt{6 - (5)}}{2}$

Simplify the result.

Simplify the numerator.

Multiply $- 1$ by $5$ .

$f (5) = \frac{6 - \sqrt{6 - 5}}{2}$

Subtract $5$ from $6$ .

$f (5) = \frac{6 - \sqrt{1}}{2}$

Any root of $1$ is $1$ .

$f (5) = \frac{6 - 1 \cdot 1}{2}$

Multiply $- 1$ by $1$ .

$f (5) = \frac{6 - 1}{2}$

Subtract $1$ from $6$ .

$f (5) = \frac{5}{2}$

The final answer is $\frac{5}{2}$ .

$y = \frac{5}{2}$

The square root can be graphed using the points around the vertex $(6, 3), (4, 2.29), (5, 2.5)$

$\begin{array}{c} x & y \\ 4 & 2.29 \\ 5 & 2.5 \\ 6 & 3 \end{array}$

Graph y=3-1/2 square root of 6-x

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