Graph y=3/2 square root of x+4

$y = \frac{3}{2} \sqrt{x} + 4$

Find the domain for $y = \frac{3}{2} \cdot \sqrt{x} + 4$ so that a list of $x$ values can be picked to find a list of points, which will help graphing the radical.

Set the radicand in $\sqrt{x}$ greater than or equal to $0$ to find where the expression is defined.

$x \geq 0$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[0, \infty)$

Set-Builder Notation:

${x | x \geq 0}$

Interval Notation:

$[0, \infty)$

Set-Builder Notation:

${x | x \geq 0}$

To find the radical expression end point, substitute the $x$ value $0$ , which is the least value in the domain, into $f (x) = \frac{3 \sqrt{x}}{2} + 4$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = \frac{3 \sqrt{0}}{2} + 4$

Simplify the result.

Simplify each term.

Simplify the numerator.

Rewrite $0$ as $0^{2}$ .

$f (0) = \frac{3 \sqrt{0^{2}}}{2} + 4$

Pull terms out from under the radical, assuming positive real numbers.

$f (0) = \frac{3 \cdot 0}{2} + 4$

Multiply $3$ by $0$ .

$f (0) = \frac{0}{2} + 4$

Divide $0$ by $2$ .

$f (0) = 0 + 4$

Add $0$ and $4$ .

$f (0) = 4$

The final answer is $4$ .

$4$

The radical expression end point is $(0, 4)$ .

$(0, 4)$

Select a few $x$ values from the domain. It would be more useful to select the values so that they are next to the $x$ value of the radical expression end point.

Substitute the $x$ value $1$ into $f (x) = \frac{3 \sqrt{x}}{2} + 4$ . In this case, the point is $(1, \frac{11}{2})$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \frac{3 \sqrt{1}}{2} + 4$

Simplify the result.

Simplify each term.

Any root of $1$ is $1$ .

$f (1) = \frac{3 \cdot 1}{2} + 4$

Multiply $3$ by $1$ .

$f (1) = \frac{3}{2} + 4$

To write $4$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f (1) = \frac{3}{2} + 4 \cdot \frac{2}{2}$

Combine $4$ and $\frac{2}{2}$ .

$f (1) = \frac{3}{2} + \frac{4 \cdot 2}{2}$

Combine the numerators over the common denominator.

$f (1) = \frac{3 + 4 \cdot 2}{2}$

Simplify the numerator.

Multiply $4$ by $2$ .

$f (1) = \frac{3 + 8}{2}$

Add $3$ and $8$ .

$f (1) = \frac{11}{2}$

The final answer is $\frac{11}{2}$ .

$y = \frac{11}{2}$

Substitute the $x$ value $2$ into $f (x) = \frac{3 \sqrt{x}}{2} + 4$ . In this case, the point is $(2, \frac{3 \sqrt{2}}{2} + 4)$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \frac{3 \sqrt{2}}{2} + 4$

The final answer is $\frac{3 \sqrt{2}}{2} + 4$ .

$y = \frac{3 \sqrt{2}}{2} + 4$

The square root can be graphed using the points around the vertex $(0, 4), (1, 5.5), (2, 6.12)$

$\begin{array}{c} x & y \\ 0 & 4 \\ 1 & 5.5 \\ 2 & 6.12 \end{array}$

Graph y=3/2 square root of x+4

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