Graph y<=3/2(x+1)

$y \leq \frac{3}{2} (x + 1)$

Step 1

Write in $y = m x + b$ form.

Simplify $\frac{3}{2} \cdot (x + 1)$ .

Apply the distributive property.

$y \leq \frac{3}{2} x + \frac{3}{2} \cdot 1$

Combine $\frac{3}{2}$ and $x$ .

$y \leq \frac{3 x}{2} + \frac{3}{2} \cdot 1$

Multiply $\frac{3}{2}$ by $1$ .

$y \leq \frac{3 x}{2} + \frac{3}{2}$

Reorder terms.

$y \leq \frac{3}{2} x + \frac{3}{2}$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{3}{2}$

$b = \frac{3}{2}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{3}{2}$

y-intercept: $(0, \frac{3}{2})$

Slope: $\frac{3}{2}$

y-intercept: $(0, \frac{3}{2})$

Step 3

Graph a solid line, then shade the area below the boundary line since $y$ is less than $\frac{3}{2} x + \frac{3}{2}$ .

$y \leq \frac{3}{2} x + \frac{3}{2}$

Step 4