Graph y=-3/2x^2

$y = - \frac{3}{2} x^{2}$

Step 1

Simplify $- \frac{3}{2} x^{2}$ .

Combine $x^{2}$ and $\frac{3}{2}$ .

$y = - \frac{x^{2} \cdot 3}{2}$

Move $3$ to the left of $x^{2}$ .

$y = - \frac{3 x^{2}}{2}$

Step 2

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $- \frac{3 x^{2}}{2}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - \frac{3}{2}$

$b = 0$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (- \frac{3}{2})}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (- \frac{3}{2})}$

Cancel the common factors.

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (- \frac{3}{2})}$

Rewrite the expression.

$d = \frac{0}{- \frac{3}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 0 (- \frac{2}{3})$

Multiply $0 (- \frac{2}{3})$ .

Multiply $- 1$ by $0$ .

$d = 0 (\frac{2}{3})$

Multiply $0$ by $\frac{2}{3}$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 (- \frac{3}{2})}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 (- \frac{3}{2})}$

Simplify the denominator.

Multiply $- 1$ by $4$ .

$e = 0 - \frac{0}{- 4 (\frac{3}{2})}$

Combine $- 4$ and $\frac{3}{2}$ .

$e = 0 - \frac{0}{\frac{- 4 \cdot 3}{2}}$

Multiply $- 4$ by $3$ .

$e = 0 - \frac{0}{\frac{- 12}{2}}$

Divide $- 12$ by $2$ .

$e = 0 - \frac{0}{- 6}$

Divide $0$ by $- 6$ .

$e = 0 - 0$

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Add $0$ and $0$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- \frac{3}{2} x^{2}$ .

$- \frac{3}{2} x^{2}$

Set $y$ equal to the new right side.

$y = - \frac{3}{2} x^{2}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - \frac{3}{2}$

$h = 0$

$k = 0$

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Find the vertex $(h, k)$ .

$(0, 0)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot (- \frac{3}{2})}$

Simplify.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1)}{4 \cdot (- \frac{3}{2})}$

Move the negative in front of the fraction.

$- \frac{1}{4 (\frac{3}{2})}$

Combine $4$ and $\frac{3}{2}$ .

$- \frac{1}{\frac{4 \cdot 3}{2}}$

Simplify the expression.

Multiply $4$ by $3$ .

$- \frac{1}{\frac{12}{2}}$

Divide $12$ by $2$ .

$- \frac{1}{6}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(0, - \frac{1}{6})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 0$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = \frac{1}{6}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Down

Vertex: $(0, 0)$

Focus: $(0, - \frac{1}{6})$

Axis of Symmetry: $x = 0$

Directrix: $y = \frac{1}{6}$

Direction: Opens Down

Vertex: $(0, 0)$

Focus: $(0, - \frac{1}{6})$

Axis of Symmetry: $x = 0$

Directrix: $y = \frac{1}{6}$

Step 3

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = - \frac{3 {(- 2)}^{2}}{2}$

Simplify the result.

Cancel the common factor of ${(- 2)}^{2}$ and $2$ .

Rewrite $- 2$ as $- 1 (2)$ .

$f (- 2) = - \frac{3 {(- 1 \cdot 2)}^{2}}{2}$

Apply the product rule to $- 1 (2)$ .

$f (- 2) = - \frac{3 ({(- 1)}^{2} \cdot 2^{2})}{2}$

Raise $- 1$ to the power of $2$ .

$f (- 2) = - \frac{3 (1 \cdot 2^{2})}{2}$

Multiply $2^{2}$ by $1$ .

$f (- 2) = - \frac{3 \cdot 2^{2}}{2}$

Factor $2$ out of $3 \cdot 2^{2}$ .

$f (- 2) = - \frac{2 (3 \cdot 2)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$f (- 2) = - \frac{2 (3 \cdot 2)}{2 (1)}$

Cancel the common factor.

$f (- 2) = - \frac{2 (3 \cdot 2)}{2 \cdot 1}$

Rewrite the expression.

$f (- 2) = - \frac{3 \cdot 2}{1}$

Divide $3 \cdot 2$ by $1$ .

$f (- 2) = - (3 \cdot 2)$

Multiply $- (3 \cdot 2)$ .

Multiply $3$ by $2$ .

$f (- 2) = - 1 \cdot 6$

Multiply $- 1$ by $6$ .

$f (- 2) = - 6$

The final answer is $- 6$ .

$- 6$

The $y$ value at $x = - 2$ is $- 6$ .

$y = - 6$

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - \frac{3 {(- 1)}^{2}}{2}$

Simplify the result.

Raise $- 1$ to the power of $2$ .

$f (- 1) = - \frac{3 \cdot 1}{2}$

Multiply $3$ by $1$ .

$f (- 1) = - \frac{3}{2}$

The final answer is $- \frac{3}{2}$ .

$- \frac{3}{2}$

The $y$ value at $x = - 1$ is $- \frac{3}{2}$ .

$y = - \frac{3}{2}$

Replace the variable $x$ with $2$ in the expression.

$f (2) = - \frac{3 {(2)}^{2}}{2}$

Simplify the result.

Cancel the common factor of ${(2)}^{2}$ and $2$ .

Factor $2$ out of $3 {(2)}^{2}$ .

$f (2) = - \frac{2 (3 \cdot 2)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$f (2) = - \frac{2 (3 \cdot 2)}{2 (1)}$

Cancel the common factor.

$f (2) = - \frac{2 (3 \cdot 2)}{2 \cdot 1}$

Rewrite the expression.

$f (2) = - \frac{3 \cdot 2}{1}$

Divide $3 \cdot 2$ by $1$ .

$f (2) = - (3 \cdot 2)$

Multiply $- (3 \cdot 2)$ .

Multiply $3$ by $2$ .

$f (2) = - 1 \cdot 6$

Multiply $- 1$ by $6$ .

$f (2) = - 6$

The final answer is $- 6$ .

$- 6$

The $y$ value at $x = 2$ is $- 6$ .

$y = - 6$

Replace the variable $x$ with $1$ in the expression.

$f (1) = - \frac{3 {(1)}^{2}}{2}$

Simplify the result.

One to any power is one.

$f (1) = - \frac{3 \cdot 1}{2}$

Multiply $3$ by $1$ .

$f (1) = - \frac{3}{2}$

The final answer is $- \frac{3}{2}$ .

$- \frac{3}{2}$

The $y$ value at $x = 1$ is $- \frac{3}{2}$ .

$y = - \frac{3}{2}$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 2 & - 6 \\ - 1 & - \frac{3}{2} \\ 0 & 0 \\ 1 & - \frac{3}{2} \\ 2 & - 6 \end{array}$

Step 4

Graph the parabola using its properties and the selected points.

Direction: Opens Down

Vertex: $(0, 0)$

Focus: $(0, - \frac{1}{6})$

Axis of Symmetry: $x = 0$

Directrix: $y = \frac{1}{6}$

$\begin{array}{c} x & y \\ - 2 & - 6 \\ - 1 & - \frac{3}{2} \\ 0 & 0 \\ 1 & - \frac{3}{2} \\ 2 & - 6 \end{array}$

Step 5

Graph y=-3/2x^2

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