Graph y>=-3 square root of x-1+2

$y \geq - 3 \sqrt{x - 1} + 2$

Step 1

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 2

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- 3 \sqrt{x - 1} + 2$ .

$y \geq - 3 \sqrt{x - 1} + 2$

Step 3