Graph y<-3x-2 y>-3x+8

$y < - 3 x - 2$ $y > - 3 x + 8$

Step 1

Graph $y < - 3 x - 2$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 3$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 3$

y-intercept: $(0, - 2)$

Slope: $- 3$

y-intercept: $(0, - 2)$

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $- 3 x - 2$ .

$y < - 3 x - 2$

Step 2

Graph $y > - 3 x + 8$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 3$

$b = 8$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 3$

y-intercept: $(0, 8)$

Slope: $- 3$

y-intercept: $(0, 8)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- 3 x + 8$ .

$y > - 3 x + 8$

Step 3

Plot each graph on the same coordinate system.

$y < - 3 x - 2$

$y > - 3 x + 8$

Step 4