Graph y>=- square root of 3x-6-5

$y \geq - \sqrt{3 x - 6} - 5$

Step 1

Factor $3$ out of $3 x - 6$ .

Factor $3$ out of $3 x$ .

$y \geq - \sqrt{3 (x) - 6} - 5$

Factor $3$ out of $- 6$ .

$y \geq - \sqrt{3 x + 3 \cdot - 2} - 5$

Factor $3$ out of $3 x + 3 \cdot - 2$ .

$y \geq - \sqrt{3 (x - 2)} - 5$

Step 2

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 3

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- \sqrt{3 (x - 2)} - 5$ .

$y \geq - \sqrt{3 (x - 2)} - 5$

Step 4