Graph y>=x^2-25 x-y>=-5

$y \geq x^{2} - 25$ $x - y \geq - 5$

Step 1

Graph $y \geq x^{2} - 25$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x^{2} - 25$ .

$y \geq x^{2} - 25$

Step 2

Graph $x - y \geq - 5$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$- y \geq - 5 - x$

Divide each term in $- y \geq - 5 - x$ by $- 1$ and simplify.

Divide each term in $- y \geq - 5 - x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \leq \frac{- 5}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \leq \frac{- 5}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y \leq \frac{- 5}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 5$ by $- 1$ .

$y \leq 5 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y \leq 5 + \frac{x}{1}$

Divide $x$ by $1$ .

$y \leq 5 + x$

Rearrange terms.

$y \leq x + 5$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = 5$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, 5)$

Slope: $1$

y-intercept: $(0, 5)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x + 5$ .

$y \leq x + 5$

Step 3

Plot each graph on the same coordinate system.

$y \geq x^{2} - 25$

$x - y \geq - 5$

Step 4

Graph y>=x^2-25 x-y>=-5

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