Graph y=-x^2+2x+5

$y = - x^{2} + 2 x + 5$

Step 1

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $- x^{2} + 2 x + 5$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = 2$

$c = 5$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{2}{2 \cdot - 1}$

Simplify the right side.

Cancel the common factor of $2$ .

Cancel the common factor.

$d = \frac{2}{2 \cdot - 1}$

Rewrite the expression.

$d = \frac{1}{- 1}$

Move the negative one from the denominator of $\frac{1}{- 1}$ .

$d = - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$d = - 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 5 - \frac{2^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Raise $2$ to the power of $2$ .

$e = 5 - \frac{4}{4 \cdot - 1}$

Multiply $4$ by $- 1$ .

$e = 5 - \frac{4}{- 4}$

Divide $4$ by $- 4$ .

$e = 5 - - 1$

Multiply $- 1$ by $- 1$ .

$e = 5 + 1$

Add $5$ and $1$ .

$e = 6$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(x - 1)}^{2} + 6$ .

$- {(x - 1)}^{2} + 6$

Set $y$ equal to the new right side.

$y = - {(x - 1)}^{2} + 6$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 1$

$k = 6$

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Find the vertex $(h, k)$ .

$(1, 6)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 1}$

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1)}{4 \cdot - 1}$

Move the negative in front of the fraction.

$- \frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(1, \frac{23}{4})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 1$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = \frac{25}{4}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Down

Vertex: $(1, 6)$

Focus: $(1, \frac{23}{4})$

Axis of Symmetry: $x = 1$

Directrix: $y = \frac{25}{4}$

Direction: Opens Down

Vertex: $(1, 6)$

Focus: $(1, \frac{23}{4})$

Axis of Symmetry: $x = 1$

Directrix: $y = \frac{25}{4}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $0$ in the expression.

$f (0) = - {(0)}^{2} + 2 (0) + 5$

Simplify the result.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = - 0 + 2 (0) + 5$

Multiply $- 1$ by $0$ .

$f (0) = 0 + 2 (0) + 5$

Multiply $2$ by $0$ .

$f (0) = 0 + 0 + 5$

Simplify by adding numbers.

Add $0$ and $0$ .

$f (0) = 0 + 5$

Add $0$ and $5$ .

$f (0) = 5$

The final answer is $5$ .

$5$

The $y$ value at $x = 0$ is $5$ .

$y = 5$

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - {(- 1)}^{2} + 2 (- 1) + 5$

Simplify the result.

Simplify each term.

Multiply $- 1$ by ${(- 1)}^{2}$ by adding the exponents.

Multiply $- 1$ by ${(- 1)}^{2}$ .

Raise $- 1$ to the power of $1$ .

$f (- 1) = (- 1) {(- 1)}^{2} + 2 (- 1) + 5$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (- 1) = {(- 1)}^{1 + 2} + 2 (- 1) + 5$

Add $1$ and $2$ .

$f (- 1) = {(- 1)}^{3} + 2 (- 1) + 5$

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 1 + 2 (- 1) + 5$

Multiply $2$ by $- 1$ .

$f (- 1) = - 1 - 2 + 5$

Simplify by adding and subtracting.

Subtract $2$ from $- 1$ .

$f (- 1) = - 3 + 5$

Add $- 3$ and $5$ .

$f (- 1) = 2$

The final answer is $2$ .

$2$

The $y$ value at $x = - 1$ is $2$ .

$y = 2$

Replace the variable $x$ with $2$ in the expression.

$f (2) = - {(2)}^{2} + 2 (2) + 5$

Simplify the result.

Simplify each term.

Raise $2$ to the power of $2$ .

$f (2) = - 1 \cdot 4 + 2 (2) + 5$

Multiply $- 1$ by $4$ .

$f (2) = - 4 + 2 (2) + 5$

Multiply $2$ by $2$ .

$f (2) = - 4 + 4 + 5$

Simplify by adding numbers.

Add $- 4$ and $4$ .

$f (2) = 0 + 5$

Add $0$ and $5$ .

$f (2) = 5$

The final answer is $5$ .

$5$

The $y$ value at $x = 2$ is $5$ .

$y = 5$

Replace the variable $x$ with $3$ in the expression.

$f (3) = - {(3)}^{2} + 2 (3) + 5$

Simplify the result.

Simplify each term.

Raise $3$ to the power of $2$ .

$f (3) = - 1 \cdot 9 + 2 (3) + 5$

Multiply $- 1$ by $9$ .

$f (3) = - 9 + 2 (3) + 5$

Multiply $2$ by $3$ .

$f (3) = - 9 + 6 + 5$

Simplify by adding numbers.

Add $- 9$ and $6$ .

$f (3) = - 3 + 5$

Add $- 3$ and $5$ .

$f (3) = 2$

The final answer is $2$ .

$2$

The $y$ value at $x = 3$ is $2$ .

$y = 2$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 1 & 2 \\ 0 & 5 \\ 1 & 6 \\ 2 & 5 \\ 3 & 2 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Down

Vertex: $(1, 6)$

Focus: $(1, \frac{23}{4})$

Axis of Symmetry: $x = 1$

Directrix: $y = \frac{25}{4}$

$\begin{array}{c} x & y \\ - 1 & 2 \\ 0 & 5 \\ 1 & 6 \\ 2 & 5 \\ 3 & 2 \end{array}$

Step 4

Graph y=-x^2+2x+5

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