Graph y>=x^2+2x-8

$y \geq x^{2} + 2 x - 8$

Step 1

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 2

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x^{2} + 2 x - 8$ .

$y \geq x^{2} + 2 x - 8$

Step 3