Graph y<=x^2+4x+3

$y \leq x^{2} + 4 x + 3$

Step 1

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 2

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x^{2} + 4 x + 3$ .

$y \leq x^{2} + 4 x + 3$

Step 3