Graph y>=x^2+4x-3

$y \geq x^{2} + 4 x - 3$

Step 1

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 2

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x^{2} + 4 x - 3$ .

$y \geq x^{2} + 4 x - 3$

Step 3