Graph y>=x^2+6x+10 y<-x^2-8x-14

$y \geq x^{2} + 6 x + 10$ $y < - x^{2} - 8 x - 14$

Step 1

Graph $y \geq x^{2} + 6 x + 10$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x^{2} + 6 x + 10$ .

$y \geq x^{2} + 6 x + 10$

Step 2

Graph $y < - x^{2} - 8 x - 14$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $- x^{2} - 8 x - 14$ .

$y < - x^{2} - 8 x - 14$

Step 3

Plot each graph on the same coordinate system.

$y \geq x^{2} + 6 x + 10$

$y < - x^{2} - 8 x - 14$

Step 4