Graph y>x^2-6x+8 x>=y^2-6y+8

$y > x^{2} - 6 x + 8$ $x \geq y^{2} - 6 y + 8$

Graph $y > x^{2} - 6 x + 8$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $x^{2} - 6 x + 8$ .

$y > x^{2} - 6 x + 8$

Cannot graph imaginary numbers.

$x \geq y^{2} - 6 y + 8$

Plot each graph on the same coordinate system.

$y > x^{2} - 6 x + 8$

$x \geq y^{2} - 6 y + 8$