Graph y=x^2-x+5

$y = x^{2} - x + 5$

Step 1

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $x^{2} - x + 5$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 1$

$c = 5$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 1}{2 \cdot 1}$

Simplify the right side.

Cancel the common factor of $- 1$ and $1$ .

Rewrite $- 1$ as $- 1 (1)$ .

$d = \frac{- 1 (1)}{2 \cdot 1}$

Cancel the common factor.

$d = \frac{- 1 \cdot 1}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 1}{2}$

Move the negative in front of the fraction.

$d = - \frac{1}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 5 - \frac{{(- 1)}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $- 1$ to the power of $2$ .

$e = 5 - \frac{1}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 5 - \frac{1}{4}$

To write $5$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = 5 \cdot \frac{4}{4} - \frac{1}{4}$

Combine $5$ and $\frac{4}{4}$ .

$e = \frac{5 \cdot 4}{4} - \frac{1}{4}$

Combine the numerators over the common denominator.

$e = \frac{5 \cdot 4 - 1}{4}$

Simplify the numerator.

Multiply $5$ by $4$ .

$e = \frac{20 - 1}{4}$

Subtract $1$ from $20$ .

$e = \frac{19}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - \frac{1}{2})}^{2} + \frac{19}{4}$ .

${(x - \frac{1}{2})}^{2} + \frac{19}{4}$

Set $y$ equal to the new right side.

$y = {(x - \frac{1}{2})}^{2} + \frac{19}{4}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = \frac{1}{2}$

$k = \frac{19}{4}$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(\frac{1}{2}, \frac{19}{4})$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{1}{2}, 5)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = \frac{1}{2}$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = \frac{9}{2}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(\frac{1}{2}, \frac{19}{4})$

Focus: $(\frac{1}{2}, 5)$

Axis of Symmetry: $x = \frac{1}{2}$

Directrix: $y = \frac{9}{2}$

Direction: Opens Up

Vertex: $(\frac{1}{2}, \frac{19}{4})$

Focus: $(\frac{1}{2}, 5)$

Axis of Symmetry: $x = \frac{1}{2}$

Directrix: $y = \frac{9}{2}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{2} - (- 1) + 5$

Simplify the result.

Simplify each term.

Raise $- 1$ to the power of $2$ .

$f (- 1) = 1 - (- 1) + 5$

Multiply $- 1$ by $- 1$ .

$f (- 1) = 1 + 1 + 5$

Simplify by adding numbers.

Add $1$ and $1$ .

$f (- 1) = 2 + 5$

Add $2$ and $5$ .

$f (- 1) = 7$

The final answer is $7$ .

$7$

The $y$ value at $x = - 1$ is $7$ .

$y = 7$

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = {(- 2)}^{2} - (- 2) + 5$

Simplify the result.

Simplify each term.

Raise $- 2$ to the power of $2$ .

$f (- 2) = 4 - (- 2) + 5$

Multiply $- 1$ by $- 2$ .

$f (- 2) = 4 + 2 + 5$

Simplify by adding numbers.

Add $4$ and $2$ .

$f (- 2) = 6 + 5$

Add $6$ and $5$ .

$f (- 2) = 11$

The final answer is $11$ .

$11$

The $y$ value at $x = - 2$ is $11$ .

$y = 11$

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{2} - (1) + 5$

Simplify the result.

Simplify each term.

One to any power is one.

$f (1) = 1 - (1) + 5$

Multiply $- 1$ by $1$ .

$f (1) = 1 - 1 + 5$

Simplify by adding and subtracting.

Subtract $1$ from $1$ .

$f (1) = 0 + 5$

Add $0$ and $5$ .

$f (1) = 5$

The final answer is $5$ .

$5$

The $y$ value at $x = 1$ is $5$ .

$y = 5$

Replace the variable $x$ with $2$ in the expression.

$f (2) = {(2)}^{2} - (2) + 5$

Simplify the result.

Simplify each term.

Raise $2$ to the power of $2$ .

$f (2) = 4 - (2) + 5$

Multiply $- 1$ by $2$ .

$f (2) = 4 - 2 + 5$

Simplify by adding and subtracting.

Subtract $2$ from $4$ .

$f (2) = 2 + 5$

Add $2$ and $5$ .

$f (2) = 7$

The final answer is $7$ .

$7$

The $y$ value at $x = 2$ is $7$ .

$y = 7$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 2 & 11 \\ - 1 & 7 \\ \frac{1}{2} & \frac{19}{4} \\ 1 & 5 \\ 2 & 7 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(\frac{1}{2}, \frac{19}{4})$

Focus: $(\frac{1}{2}, 5)$

Axis of Symmetry: $x = \frac{1}{2}$

Directrix: $y = \frac{9}{2}$

$\begin{array}{c} x & y \\ - 2 & 11 \\ - 1 & 7 \\ \frac{1}{2} & \frac{19}{4} \\ 1 & 5 \\ 2 & 7 \end{array}$

Step 4

Graph y=x^2-x+5

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