Graph y<=x+3/2

$y \leq x + \frac{3}{2}$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = \frac{3}{2}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, \frac{3}{2})$

Slope: $1$

y-intercept: $(0, \frac{3}{2})$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x + \frac{3}{2}$ .

$y \leq x + \frac{3}{2}$