Graph y=x^3+x^2+x+1

$y = x^{3} + x^{2} + x + 1$

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = {(- 2)}^{3} + {(- 2)}^{2} - 2 + 1$

Simplify the result.

Remove parentheses.

$f (- 2) = {(- 2)}^{3} + {(- 2)}^{2} - 2 + 1$

Simplify each term.

Raise $- 2$ to the power of $3$ .

$f (- 2) = - 8 + {(- 2)}^{2} - 2 + 1$

Raise $- 2$ to the power of $2$ .

$f (- 2) = - 8 + 4 - 2 + 1$

Simplify by adding and subtracting.

Add $- 8$ and $4$ .

$f (- 2) = - 4 - 2 + 1$

Subtract $2$ from $- 4$ .

$f (- 2) = - 6 + 1$

Add $- 6$ and $1$ .

$f (- 2) = - 5$

The final answer is $- 5$ .

$- 5$

Convert $- 5$ to decimal.

$y = - 5$

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{3} + {(- 1)}^{2} - 1 + 1$

Simplify the result.

Remove parentheses.

$f (- 1) = {(- 1)}^{3} + {(- 1)}^{2} - 1 + 1$

Simplify each term.

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 1 + {(- 1)}^{2} - 1 + 1$

Raise $- 1$ to the power of $2$ .

$f (- 1) = - 1 + 1 - 1 + 1$

Simplify by adding and subtracting.

Add $- 1$ and $1$ .

$f (- 1) = 0 - 1 + 1$

Subtract $1$ from $0$ .

$f (- 1) = - 1 + 1$

Add $- 1$ and $1$ .

$f (- 1) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{3} + {(0)}^{2} + 0 + 1$

Simplify the result.

Remove parentheses.

$f (0) = {(0)}^{3} + {(0)}^{2} + 0 + 1$

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 + {(0)}^{2} + 0 + 1$

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 + 0 + 0 + 1$

Simplify by adding numbers.

Add $0$ and $0$ .

$f (0) = 0 + 0 + 1$

Add $0$ and $0$ .

$f (0) = 0 + 1$

Add $0$ and $1$ .

$f (0) = 1$

The final answer is $1$ .

$1$

Convert $1$ to decimal.

$y = 1$

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{3} + {(1)}^{2} + 1 + 1$

Simplify the result.

Remove parentheses.

$f (1) = {(1)}^{3} + {(1)}^{2} + 1 + 1$

Simplify each term.

One to any power is one.

$f (1) = 1 + {(1)}^{2} + 1 + 1$

One to any power is one.

$f (1) = 1 + 1 + 1 + 1$

Simplify by adding numbers.

Add $1$ and $1$ .

$f (1) = 2 + 1 + 1$

Add $2$ and $1$ .

$f (1) = 3 + 1$

Add $3$ and $1$ .

$f (1) = 4$

The final answer is $4$ .

$4$

Convert $4$ to decimal.

$y = 4$

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = {(2)}^{3} + {(2)}^{2} + 2 + 1$

Simplify the result.

Remove parentheses.

$f (2) = {(2)}^{3} + {(2)}^{2} + 2 + 1$

Simplify each term.

Raise $2$ to the power of $3$ .

$f (2) = 8 + {(2)}^{2} + 2 + 1$

Raise $2$ to the power of $2$ .

$f (2) = 8 + 4 + 2 + 1$

Simplify by adding numbers.

Add $8$ and $4$ .

$f (2) = 12 + 2 + 1$

Add $12$ and $2$ .

$f (2) = 14 + 1$

Add $14$ and $1$ .

$f (2) = 15$

The final answer is $15$ .

$15$

Convert $15$ to decimal.

$y = 15$

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & - 5 \\ - 1 & 0 \\ 0 & 1 \\ 1 & 4 \\ 2 & 15 \end{array}$

The cubic function can be graphed using the function behavior and the selected points.

Falls to the left and rises to the right

$\begin{array}{c} x & y \\ - 2 & - 5 \\ - 1 & 0 \\ 0 & 1 \\ 1 & 4 \\ 2 & 15 \end{array}$

Graph y=x^3+x^2+x+1

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