Graph y=(x-3)(x-3)

$y = (x - 3) (x - 3)$

Step 1

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $(x - 3) (x - 3)$ .

Simplify the expression.

Expand $(x - 3) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (x - 3) - 3 (x - 3)$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 (x - 3)$

Apply the distributive property.

$x \cdot x + x \cdot - 3 - 3 x - 3 \cdot - 3$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 3 - 3 x - 3 \cdot - 3$

Move $- 3$ to the left of $x$ .

$x^{2} - 3 \cdot x - 3 x - 3 \cdot - 3$

Multiply $- 3$ by $- 3$ .

$x^{2} - 3 x - 3 x + 9$

Subtract $3 x$ from $- 3 x$ .

$x^{2} - 6 x + 9$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 6$

$c = 9$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 6}{2 \cdot 1}$

Cancel the common factor of $- 6$ and $2$ .

Factor $2$ out of $- 6$ .

$d = \frac{2 \cdot - 3}{2 \cdot 1}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 3}{2 (1)}$

Cancel the common factor.

$d = \frac{2 \cdot - 3}{2 \cdot 1}$

Rewrite the expression.

$d = \frac{- 3}{1}$

Divide $- 3$ by $1$ .

$d = - 3$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 9 - \frac{{(- 6)}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $- 6$ to the power of $2$ .

$e = 9 - \frac{36}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 9 - \frac{36}{4}$

Divide $36$ by $4$ .

$e = 9 - 1 \cdot 9$

Multiply $- 1$ by $9$ .

$e = 9 - 9$

Subtract $9$ from $9$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - 3)}^{2} + 0$ .

${(x - 3)}^{2} + 0$

Set $y$ equal to the new right side.

$y = {(x - 3)}^{2} + 0$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 3$

$k = 0$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(3, 0)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(3, \frac{1}{4})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 3$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{1}{4}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(3, 0)$

Focus: $(3, \frac{1}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{1}{4}$

Direction: Opens Up

Vertex: $(3, 0)$

Focus: $(3, \frac{1}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{1}{4}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $2$ in the expression.

$f (2) = ((2) - 3) ((2) - 3)$

Simplify the result.

Subtract $3$ from $2$ .

$f (2) = - 1 ((2) - 3)$

Subtract $3$ from $2$ .

$f (2) = - 1 \cdot - 1$

Multiply $- 1$ by $- 1$ .

$f (2) = 1$

The final answer is $1$ .

$1$

The $y$ value at $x = 2$ is $1$ .

$y = 1$

Replace the variable $x$ with $1$ in the expression.

$f (1) = ((1) - 3) ((1) - 3)$

Simplify the result.

Subtract $3$ from $1$ .

$f (1) = - 2 ((1) - 3)$

Subtract $3$ from $1$ .

$f (1) = - 2 \cdot - 2$

Multiply $- 2$ by $- 2$ .

$f (1) = 4$

The final answer is $4$ .

$4$

The $y$ value at $x = 1$ is $4$ .

$y = 4$

Replace the variable $x$ with $4$ in the expression.

$f (4) = ((4) - 3) ((4) - 3)$

Simplify the result.

Subtract $3$ from $4$ .

$f (4) = 1 ((4) - 3)$

Multiply $(4) - 3$ by $1$ .

$f (4) = (4) - 3$

Subtract $3$ from $4$ .

$f (4) = 1$

The final answer is $1$ .

$1$

The $y$ value at $x = 4$ is $1$ .

$y = 1$

Replace the variable $x$ with $5$ in the expression.

$f (5) = ((5) - 3) ((5) - 3)$

Simplify the result.

Subtract $3$ from $5$ .

$f (5) = 2 ((5) - 3)$

Subtract $3$ from $5$ .

$f (5) = 2 \cdot 2$

Multiply $2$ by $2$ .

$f (5) = 4$

The final answer is $4$ .

$4$

The $y$ value at $x = 5$ is $4$ .

$y = 4$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ 1 & 4 \\ 2 & 1 \\ 3 & 0 \\ 4 & 1 \\ 5 & 4 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(3, 0)$

Focus: $(3, \frac{1}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{1}{4}$

$\begin{array}{c} x & y \\ 1 & 4 \\ 2 & 1 \\ 3 & 0 \\ 4 & 1 \\ 5 & 4 \end{array}$

Step 4

Graph y=(x-3)(x-3)

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