Graph y<=-x+4 , y=0 , x>=0

$y \leq - x + 4$ , $y = 0$ , $x \geq 0$

Graph $y \leq - x + 4$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 4$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 4)$

Slope: $- 1$

y-intercept: $(0, 4)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- x + 4$ .

$y \leq - x + 4$

Graph $y = 0$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 0$

$b = 0$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $0$

y-intercept: $(0, 0)$

Slope: $0$

y-intercept: $(0, 0)$

Find two points on the line.

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 0 \end{array}$

Graph the line using the slope, y-intercept, and two points.

Slope: $0$

y-intercept: $(0, 0)$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 0 \end{array}$

Slope: $0$

y-intercept: $(0, 0)$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 0 \end{array}$

Graph $x \geq 0$ .

$x \geq 0$

Plot each graph on the same coordinate system.

$y \leq - x + 4$

$y = 0$

$x \geq 0$