Identify the Progression 0 , 2 , 6 , 12 , 20

$0$ , $2$ , $6$ , $12$ , $20$

Find the first level differences by finding the differences between consecutive terms.

$2, 4, 6, 8$

Find the second level difference by finding the differences between the first level differences. Because the second level difference is constant, the sequence is quadratic and given by $a_{n} = a n^{2} + b n + c$ .

$2$

Solve for $a$ by setting $2 a$ equal to the constant second level difference $2$ .

Set $2 a$ equal to the constant second level difference $2$ .

$2 a = 2$

Divide each term in $2 a = 2$ by $2$ and simplify.

Divide each term in $2 a = 2$ by $2$ .

$\frac{2 a}{2} = \frac{2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 a}{2} = \frac{2}{2}$

Divide $a$ by $1$ .

$a = \frac{2}{2}$

Simplify the right side.

Divide $2$ by $2$ .

$a = 1$

Solve for $b$ by setting $3 a + b$ equal to the first first level difference $2$ .

Set $3 a + b$ equal to the first first level difference $2$ .

$3 a + b = 2$

Substitute $1$ for $a$ .

$3 \cdot 1 + b = 2$

Multiply $3$ by $1$ .

$3 + b = 2$

Move all terms not containing $b$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$b = 2 - 3$

Subtract $3$ from $2$ .

$b = - 1$

Solve for $c$ by setting $a + b + c$ equal to the first term in the sequence $0$ .

Set $a + b + c$ equal to the first term in the sequence $0$ .

$a + b + c = 0$

Substitute $1$ for $a$ and $- 1$ for $b$ .

$1 - 1 + c = 0$

Simplify $1 - 1 + c$ .

Subtract $1$ from $1$ .

$0 + c = 0$

Add $0$ and $c$ .

$c = 0$

Substitute the values of $a$ , $b$ , and $c$ into the quadratic sequence formula $a_{n} = a n^{2} + b n + c$ .

$a_{n} = 1 n^{2} - n + 0$

Simplify.

Add $1 n^{2} - n$ and $0$ .

$a_{n} = 1 n^{2} - n$

Multiply $n^{2}$ by $1$ .

$a_{n} = n^{2} - n$

Identify the Progression 0 , 2 , 6 , 12 , 20

Related Questions

Support LCMGCF.com by disabling your adblocker.