Identify the Sequence -96 , 48 , -24 , 12 , -6

$- 96$ , $48$ , $- 24$ , $12$ , $- 6$

Step 1

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by $- \frac{1}{2}$ gives the next term. In other words, $a_{n} = a_{1} r^{n - 1}$ .

Geometric Sequence: $r = - \frac{1}{2}$

Step 2

This is the form of a geometric sequence.

$a_{n} = a_{1} r^{n - 1}$

Step 3

Substitute in the values of $a_{1} = - 96$ and $r = - \frac{1}{2}$ .

$a_{n} = - 96 {(- \frac{1}{2})}^{n - 1}$

Step 4

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{1}{2}$ .

$a_{n} = - 96 ({(- 1)}^{n - 1} {(\frac{1}{2})}^{n - 1})$

Apply the product rule to $\frac{1}{2}$ .

$a_{n} = - 96 ({(- 1)}^{n - 1} \frac{1^{n - 1}}{2^{n - 1}})$

Step 5

One to any power is one.

$a_{n} = - 96 ({(- 1)}^{n - 1} \frac{1}{2^{n - 1}})$

Step 6

Combine ${(- 1)}^{n - 1}$ and $\frac{1}{2^{n - 1}}$ .

$a_{n} = - 96 \frac{{(- 1)}^{n - 1}}{2^{n - 1}}$

Step 7

Combine $- 96$ and $\frac{{(- 1)}^{n - 1}}{2^{n - 1}}$ .

$a_{n} = \frac{- 96 {(- 1)}^{n - 1}}{2^{n - 1}}$

Step 8

Move the negative in front of the fraction.

$a_{n} = - \frac{96 {(- 1)}^{n - 1}}{2^{n - 1}}$

Identify the Sequence -96 , 48 , -24 , 12 , -6

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