Identify the Zeros and Their Multiplicities p(x)=-3(x+5)(3x-2)^2

$p (x) = - 3 (x + 5) {(3 x - 2)}^{2}$

Step 1

Set $- 3 (x + 5) {(3 x - 2)}^{2}$ equal to $0$ .

$- 3 (x + 5) {(3 x - 2)}^{2} = 0$

Step 2

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 5 = 0$

${(3 x - 2)}^{2} = 0$

Set $x + 5$ equal to $0$ and solve for $x$ .

Set $x + 5$ equal to $0$ .

$x + 5 = 0$

Subtract $5$ from both sides of the equation.

$x = - 5$

Set ${(3 x - 2)}^{2}$ equal to $0$ and solve for $x$ .

Set ${(3 x - 2)}^{2}$ equal to $0$ .

${(3 x - 2)}^{2} = 0$

Solve ${(3 x - 2)}^{2} = 0$ for $x$ .

Set the $3 x - 2$ equal to $0$ .

$3 x - 2 = 0$

Solve for $x$ .

Add $2$ to both sides of the equation.

$3 x = 2$

Divide each term in $3 x = 2$ by $3$ and simplify.

Divide each term in $3 x = 2$ by $3$ .

$\frac{3 x}{3} = \frac{2}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{2}{3}$

Divide $x$ by $1$ .

$x = \frac{2}{3}$

The final solution is all the values that make $- 3 (x + 5) {(3 x - 2)}^{2} = 0$ true. The multiplicity of a root is the number of times the root appears.

$x = - 5$ (Multiplicity of $1$ )

$x = \frac{2}{3}$ (Multiplicity of $2$ )

$x = - 5$ (Multiplicity of $1$ )

$x = \frac{2}{3}$ (Multiplicity of $2$ )

Step 3

Identify the Zeros and Their Multiplicities p(x)=-3(x+5)(3x-2)^2

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