Identify the Zeros and Their Multiplicities y=(x-12)^3-10

$y = {(x - 12)}^{3} - 10$

Step 1

Set ${(x - 12)}^{3} - 10$ equal to $0$ .

${(x - 12)}^{3} - 10 = 0$

Step 2

Solve for $x$ .

Add $10$ to both sides of the equation.

${(x - 12)}^{3} = 10$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 12 = \sqrt[3]{10}$

Add $12$ to both sides of the equation.

$x = \sqrt[3]{10} + 12$

The multiplicity of a root is the number of times the root appears. For example, a factor of ${(x + 5)}^{3}$ would have a root at $x = - 5$ with multiplicity of $3$ .

$x = \sqrt[3]{10} + 12$ (Multiplicity of $3$ )

Step 3

Identify the Zeros and Their Multiplicities y=(x-12)^3-10

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