Simplify (1+3)^2-10÷2

${(1 + 3)}^{2} - 10 \div 2$

Step 1

Simplify each term.

Add $1$ and $3$ .

$4^{2} - 10 \div 2$

Raise $4$ to the power of $2$ .

$16 - 10 \div 2$

Divide $10$ by $2$ .

$16 - 1 \cdot 5$

Multiply $- 1$ by $5$ .

$16 - 5$

$16 - 5$

Step 2

Subtract $5$ from $16$ .

$11$

Related Questions