Simplify (1/4)^(-3x)*8^(2-2x)

${(\frac{1}{4})}^{- 3 x} \cdot 8^{2 - 2 x}$

Step 1

Simplify the expression.

Apply the product rule to $\frac{1}{4}$ .

$\frac{1^{- 3 x}}{4^{- 3 x}} \cdot 8^{2 - 2 x}$

One to any power is one.

$\frac{1}{4^{- 3 x}} \cdot 8^{2 - 2 x}$

$\frac{1}{4^{- 3 x}} \cdot 8^{2 - 2 x}$

Step 2

Combine $\frac{1}{4^{- 3 x}}$ and $8^{2 - 2 x}$ .

$\frac{8^{2 - 2 x}}{4^{- 3 x}}$

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