Simplify (1-x)/(x^3-x^2-x+1)

$\frac{1 - x}{x^{3} - x^{2} - x + 1}$

Step 1

Simplify the denominator.

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{1 - x}{(x^{3} - x^{2}) - x + 1}$

Factor out the greatest common factor (GCF) from each group.

$\frac{1 - x}{x^{2} (x - 1) - (x - 1)}$

Factor the polynomial by factoring out the greatest common factor, $x - 1$ .

$\frac{1 - x}{(x - 1) (x^{2} - 1)}$

Rewrite $1$ as $1^{2}$ .

$\frac{1 - x}{(x - 1) (x^{2} - 1^{2})}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 1$ .

$\frac{1 - x}{(x - 1) (x + 1) (x - 1)}$

Combine exponents.

Raise $x - 1$ to the power of $1$ .

$\frac{1 - x}{{(x - 1)}^{1} (x - 1) (x + 1)}$

Raise $x - 1$ to the power of $1$ .

$\frac{1 - x}{{(x - 1)}^{1} {(x - 1)}^{1} (x + 1)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1 - x}{{(x - 1)}^{1 + 1} (x + 1)}$

Add $1$ and $1$ .

$\frac{1 - x}{{(x - 1)}^{2} (x + 1)}$

Step 2

Reduce the expression by cancelling the common factors.

Cancel the common factor of $1 - x$ and ${(x - 1)}^{2}$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1) - x}{{(x - 1)}^{2} (x + 1)}$

Factor $- 1$ out of $- x$ .

$\frac{- 1 (- 1) - (x)}{{(x - 1)}^{2} (x + 1)}$

Factor $- 1$ out of $- 1 (- 1) - (x)$ .

$\frac{- 1 (- 1 + x)}{{(x - 1)}^{2} (x + 1)}$

Reorder terms.

$\frac{- 1 (x - 1)}{{(x - 1)}^{2} (x + 1)}$

Factor $x - 1$ out of $- 1 (x - 1)$ .

$\frac{(x - 1) \cdot - 1}{{(x - 1)}^{2} (x + 1)}$

Cancel the common factors.

Factor $x - 1$ out of ${(x - 1)}^{2} (x + 1)$ .

$\frac{(x - 1) \cdot - 1}{(x - 1) ((x - 1) (x + 1))}$

Cancel the common factor.

$\frac{(x - 1) \cdot - 1}{(x - 1) ((x - 1) (x + 1))}$

Rewrite the expression.

$\frac{- 1}{(x - 1) (x + 1)}$

Move the negative in front of the fraction.

$- \frac{1}{(x - 1) (x + 1)}$