Simplify (10x^2+15x+20)÷(5x+5)

$(10 x^{2} + 15 x + 20) \div (5 x + 5)$

Step 1

Rewrite the division as a fraction.

$\frac{10 x^{2} + 15 x + 20}{5 x + 5}$

Step 2

Cancel the common factor of $10 x^{2} + 15 x + 20$ and $5 x + 5$ .

Factor $5$ out of $10 x^{2}$ .

$\frac{5 (2 x^{2}) + 15 x + 20}{5 x + 5}$

Factor $5$ out of $15 x$ .

$\frac{5 (2 x^{2}) + 5 (3 x) + 20}{5 x + 5}$

Factor $5$ out of $5 (2 x^{2}) + 5 (3 x)$ .

$\frac{5 (2 x^{2} + 3 x) + 20}{5 x + 5}$

Factor $5$ out of $20$ .

$\frac{5 (2 x^{2} + 3 x) + 5 \cdot 4}{5 x + 5}$

Factor $5$ out of $5 (2 x^{2} + 3 x) + 5 (4)$ .

$\frac{5 (2 x^{2} + 3 x + 4)}{5 x + 5}$

Cancel the common factors.

Factor $5$ out of $5 x$ .

$\frac{5 (2 x^{2} + 3 x + 4)}{5 (x) + 5}$

Factor $5$ out of $5$ .

$\frac{5 (2 x^{2} + 3 x + 4)}{5 (x) + 5 (1)}$

Factor $5$ out of $5 (x) + 5 (1)$ .

$\frac{5 (2 x^{2} + 3 x + 4)}{5 (x + 1)}$

Cancel the common factor.

$\frac{5 (2 x^{2} + 3 x + 4)}{5 (x + 1)}$

Rewrite the expression.

$\frac{2 x^{2} + 3 x + 4}{x + 1}$