Simplify ((10x-8)/(x+2))÷((25x^2-16)/(2x-4))

$\frac{10 x - 8}{x + 2} \div \frac{25 x^{2} - 16}{2 x - 4}$

To divide by a fraction, multiply by its reciprocal.

$\frac{10 x - 8}{x + 2} \cdot \frac{2 x - 4}{25 x^{2} - 16}$

Simplify with factoring out.

Factor $2$ out of $10 x - 8$ .

Factor $2$ out of $10 x$ .

$\frac{2 (5 x) - 8}{x + 2} \cdot \frac{2 x - 4}{25 x^{2} - 16}$

Factor $2$ out of $- 8$ .

$\frac{2 (5 x) + 2 (- 4)}{x + 2} \cdot \frac{2 x - 4}{25 x^{2} - 16}$

Factor $2$ out of $2 (5 x) + 2 (- 4)$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 x - 4}{25 x^{2} - 16}$

Factor $2$ out of $2 x - 4$ .

Factor $2$ out of $2 x$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 (x) - 4}{25 x^{2} - 16}$

Factor $2$ out of $- 4$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 x + 2 \cdot - 2}{25 x^{2} - 16}$

Factor $2$ out of $2 x + 2 \cdot - 2$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 (x - 2)}{25 x^{2} - 16}$

Simplify the denominator.

Rewrite $25 x^{2}$ as ${(5 x)}^{2}$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 (x - 2)}{{(5 x)}^{2} - 16}$

Rewrite $16$ as $4^{2}$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 (x - 2)}{{(5 x)}^{2} - 4^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5 x$ and $b = 4$ .

$\frac{2 (5 x - 4)}{x + 2} \cdot \frac{2 (x - 2)}{(5 x + 4) (5 x - 4)}$

Simplify terms.

Cancel the common factor of $5 x - 4$ .

Factor $5 x - 4$ out of $2 (5 x - 4)$ .

$\frac{(5 x - 4) \cdot 2}{x + 2} \cdot \frac{2 (x - 2)}{(5 x + 4) (5 x - 4)}$

Factor $5 x - 4$ out of $(5 x + 4) (5 x - 4)$ .

$\frac{(5 x - 4) \cdot 2}{x + 2} \cdot \frac{2 (x - 2)}{(5 x - 4) (5 x + 4)}$

Cancel the common factor.

$\frac{(5 x - 4) \cdot 2}{x + 2} \cdot \frac{2 (x - 2)}{(5 x - 4) (5 x + 4)}$

Rewrite the expression.

$\frac{2}{x + 2} \cdot \frac{2 (x - 2)}{5 x + 4}$

Multiply $\frac{2}{x + 2}$ by $\frac{2 (x - 2)}{5 x + 4}$ .

$\frac{2 (2 (x - 2))}{(x + 2) (5 x + 4)}$

Multiply $2$ by $2$ .

$\frac{4 (x - 2)}{(x + 2) (5 x + 4)}$