Simplify 12-8÷4+((6+2)-3)^2*3

$12 - 8 \div 4 + {((6 + 2) - 3)}^{2} \times 3$

Step 1

Find the common denominator.

Write $12$ as a fraction with denominator $1$ .

$\frac{12}{1} - 8 \div 4 + {((6 + 2) - 3)}^{2} \cdot 3$

Multiply $\frac{12}{1}$ by $\frac{4}{4}$ .

$\frac{12}{1} \cdot \frac{4}{4} - 8 \div 4 + {((6 + 2) - 3)}^{2} \cdot 3$

Multiply $\frac{12}{1}$ by $\frac{4}{4}$ .

$\frac{12 \cdot 4}{4} - 8 \div 4 + {((6 + 2) - 3)}^{2} \cdot 3$

Write ${((6 + 2) - 3)}^{2} \cdot 3$ as a fraction with denominator $1$ .

$\frac{12 \cdot 4}{4} - 8 \div 4 + \frac{{((6 + 2) - 3)}^{2} \cdot 3}{1}$

Multiply $\frac{{((6 + 2) - 3)}^{2} \cdot 3}{1}$ by $\frac{4}{4}$ .

$\frac{12 \cdot 4}{4} - 8 \div 4 + \frac{{((6 + 2) - 3)}^{2} \cdot 3}{1} \cdot \frac{4}{4}$

Multiply $\frac{{((6 + 2) - 3)}^{2} \cdot 3}{1}$ by $\frac{4}{4}$ .

$\frac{12 \cdot 4}{4} - 8 \div 4 + \frac{{((6 + 2) - 3)}^{2} \cdot 3 \cdot 4}{4}$

Step 2

Combine the numerators over the common denominator.

$\frac{12 \cdot 4 - 8 + {((6 + 2) - 3)}^{2} \cdot 3 \cdot 4}{4}$

Step 3

Simplify each term.

Multiply $12$ by $4$ .

$\frac{48 - 8 + {((6 + 2) - 3)}^{2} \cdot 3 \cdot 4}{4}$

Add $6$ and $2$ .

$\frac{48 - 8 + {(8 - 3)}^{2} \cdot 3 \cdot 4}{4}$

Subtract $3$ from $8$ .

$\frac{48 - 8 + 5^{2} \cdot 3 \cdot 4}{4}$

Raise $5$ to the power of $2$ .

$\frac{48 - 8 + 25 \cdot 3 \cdot 4}{4}$

Multiply $25 \cdot 3 \cdot 4$ .

Multiply $25$ by $3$ .

$\frac{48 - 8 + 75 \cdot 4}{4}$

Multiply $75$ by $4$ .

$\frac{48 - 8 + 300}{4}$

Step 4

Simplify the expression.

Subtract $8$ from $48$ .

$\frac{40 + 300}{4}$

Add $40$ and $300$ .

$\frac{340}{4}$

Divide $340$ by $4$ .

$85$