Simplify 122-3*4^2+ square root of 4-3

$122 - 3 \cdot 4^{2} + \sqrt{4 - 3}$

Step 1

Simplify each term.

Raise $4$ to the power of $2$ .

$122 - 3 \cdot 16 + \sqrt{4 - 3}$

Multiply $- 3$ by $16$ .

$122 - 48 + \sqrt{4 - 3}$

Subtract $3$ from $4$ .

$122 - 48 + \sqrt{1}$

Any root of $1$ is $1$ .

$122 - 48 + 1$

$122 - 48 + 1$

Step 2

Simplify by adding and subtracting.

Subtract $48$ from $122$ .

$74 + 1$

Add $74$ and $1$ .

$75$

$75$

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