Simplify (12x^4-4x^3+7x+6)+(3x^2-4x+14)

$(12 x^{4} - 4 x^{3} + 7 x + 6) + (3 x^{2} - 4 x + 14)$

Step 1

Remove parentheses.

$12 x^{4} - 4 x^{3} + 7 x + 6 + 3 x^{2} - 4 x + 14$

Step 2

Subtract $4 x$ from $7 x$ .

$12 x^{4} - 4 x^{3} + 3 x + 6 + 3 x^{2} + 14$

Step 3

Simplify the expression.

Add $6$ and $14$ .

$12 x^{4} - 4 x^{3} + 3 x + 3 x^{2} + 20$

Move $3 x$ .

$12 x^{4} - 4 x^{3} + 3 x^{2} + 3 x + 20$