Simplify ((143xy)^0d^-8)/(d^-5)

$\frac{{(143 x y)}^{0} d^{- 8}}{d^{- 5}}$

Step 1

Move $d^{- 8}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{d^{- 5} d^{8}}$

Step 2

Multiply $d^{- 5}$ by $d^{8}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{d^{- 5 + 8}}$

Add $- 5$ and $8$ .

$\frac{1}{d^{3}}$