Simplify (14x^0y^-2)/(2^-1z^-3)

$\frac{14 x^{0} y^{- 2}}{2^{- 1} z^{- 3}}$

Step 1

Move $y^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{14}{2^{- 1} z^{- 3} y^{2}}$

Step 2

Move $2^{- 1}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{14 \cdot 2}{z^{- 3} y^{2}}$

Step 3

Move $z^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{14 \cdot 2 z^{3}}{y^{2}}$

Step 4

Multiply $14$ by $2$ .

$\frac{28 z^{3}}{y^{2}}$