Simplify 2/(49z^3y)-1/(14z^2y)

$\frac{2}{49 z^{3} y} - \frac{1}{14 z^{2} y}$

Step 1

To write $\frac{2}{49 z^{3} y}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{2}{49 z^{3} y} \cdot \frac{2}{2} - \frac{1}{14 z^{2} y}$

Step 2

To write $- \frac{1}{14 z^{2} y}$ as a fraction with a common denominator, multiply by $\frac{7 z}{7 z}$ .

$\frac{2}{49 z^{3} y} \cdot \frac{2}{2} - \frac{1}{14 z^{2} y} \cdot \frac{7 z}{7 z}$

Step 3

Write each expression with a common denominator of $98 y z^{3}$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2}{49 z^{3} y}$ by $\frac{2}{2}$ .

$\frac{2 \cdot 2}{49 z^{3} y \cdot 2} - \frac{1}{14 z^{2} y} \cdot \frac{7 z}{7 z}$

Multiply $2$ by $49$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{1}{14 z^{2} y} \cdot \frac{7 z}{7 z}$

Multiply $\frac{1}{14 z^{2} y}$ by $\frac{7 z}{7 z}$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{14 z^{2} y (7 z)}$

Multiply $7$ by $14$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{98 z^{2} y z}$

Raise $z$ to the power of $1$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{98 y (z^{2} z^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{98 y z^{2 + 1}}$

Add $2$ and $1$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{98 y z^{3}}$

Reorder the factors of $98 y z^{3}$ .

$\frac{2 \cdot 2}{98 z^{3} y} - \frac{7 z}{98 z^{3} y}$

Step 4

Combine the numerators over the common denominator.

$\frac{2 \cdot 2 - 7 z}{98 z^{3} y}$

Step 5

Multiply $2$ by $2$ .

$\frac{4 - 7 z}{98 z^{3} y}$