Simplify 2(4i^2)+22

$2 (4 i^{2}) + 22$

Step 1

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

$2 (4 \cdot - 1) + 22$

Multiply $2 (4 \cdot - 1)$ .

Multiply $4$ by $- 1$ .

$2 \cdot - 4 + 22$

Multiply $2$ by $- 4$ .

$- 8 + 22$

$- 8 + 22$

$- 8 + 22$

Step 2

Add $- 8$ and $22$ .

$14$

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