Simplify (2/(8m^3-64m^2))÷(1/(8m^2))

$\frac{2}{8 m^{3} - 64 m^{2}} \div \frac{1}{8 m^{2}}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{2}{8 m^{3} - 64 m^{2}} (8 m^{2})$

Step 2

Rewrite using the commutative property of multiplication.

$8 \frac{2}{8 m^{3} - 64 m^{2}} m^{2}$

Step 3

Factor $8 m^{2}$ out of $8 m^{3} - 64 m^{2}$ .

Factor $8 m^{2}$ out of $8 m^{3}$ .

$8 \frac{2}{8 m^{2} (m) - 64 m^{2}} m^{2}$

Factor $8 m^{2}$ out of $- 64 m^{2}$ .

$8 \frac{2}{8 m^{2} (m) + 8 m^{2} (- 8)} m^{2}$

Factor $8 m^{2}$ out of $8 m^{2} (m) + 8 m^{2} (- 8)$ .

$8 \frac{2}{8 m^{2} (m - 8)} m^{2}$

Step 4

Cancel the common factor of $8$ .

Factor $8$ out of $8 m^{2} (m - 8)$ .

$8 \frac{2}{8 (m^{2} (m - 8))} m^{2}$

Cancel the common factor.

$8 \frac{2}{8 (m^{2} (m - 8))} m^{2}$

Rewrite the expression.

$\frac{2}{m^{2} (m - 8)} m^{2}$

Step 5

Cancel the common factor of $m^{2}$ .

Cancel the common factor.

$\frac{2}{m^{2} (m - 8)} m^{2}$

Rewrite the expression.

$\frac{2}{m - 8}$