Simplify (2(cos(pi/4)+isin(pi/4)))^4

${(2 (\cos (\frac{π}{4}) + i \sin (\frac{π}{4})))}^{4}$

Step 1

Simplify terms.

Simplify each term.

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

${(2 (\frac{\sqrt{2}}{2} + i \sin (\frac{π}{4})))}^{4}$

The exact value of $\sin (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

${(2 (\frac{\sqrt{2}}{2} + i \frac{\sqrt{2}}{2}))}^{4}$

Combine $i$ and $\frac{\sqrt{2}}{2}$ .

${(2 (\frac{\sqrt{2}}{2} + \frac{i \sqrt{2}}{2}))}^{4}$

Simplify terms.

Apply the distributive property.

${(2 \frac{\sqrt{2}}{2} + 2 \frac{i \sqrt{2}}{2})}^{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 \frac{\sqrt{2}}{2} + 2 \frac{i \sqrt{2}}{2})}^{4}$

Rewrite the expression.

${(\sqrt{2} + 2 \frac{i \sqrt{2}}{2})}^{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(\sqrt{2} + 2 \frac{i \sqrt{2}}{2})}^{4}$

Rewrite the expression.

${(\sqrt{2} + i \sqrt{2})}^{4}$

Step 2

Use the Binomial Theorem.

${\sqrt{2}}^{4} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Step 3

Simplify terms.

Simplify each term.

Rewrite ${\sqrt{2}}^{4}$ as $2^{2}$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

${(2^{\frac{1}{2}})}^{4} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$2^{\frac{1}{2} \cdot 4} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Combine $\frac{1}{2}$ and $4$ .

$2^{\frac{4}{2}} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4$ .

$2^{\frac{2 \cdot 2}{2}} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factors.

Factor $2$ out of $2$ .

$2^{\frac{2 \cdot 2}{2 (1)}} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor.

$2^{\frac{2 \cdot 2}{2 \cdot 1}} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite the expression.

$2^{\frac{2}{1}} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Divide $2$ by $1$ .

$2^{2} + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Raise $2$ to the power of $2$ .

$4 + 4 {\sqrt{2}}^{3} (i \sqrt{2}) + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply ${\sqrt{2}}^{3}$ by $\sqrt{2}$ by adding the exponents.

Move $\sqrt{2}$ .

$4 + 4 (\sqrt{2} {\sqrt{2}}^{3}) i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply $\sqrt{2}$ by ${\sqrt{2}}^{3}$ .

Raise $\sqrt{2}$ to the power of $1$ .

$4 + 4 ({\sqrt{2}}^{1} {\sqrt{2}}^{3}) i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 + 4 {\sqrt{2}}^{1 + 3} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Add $1$ and $3$ .

$4 + 4 {\sqrt{2}}^{4} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite ${\sqrt{2}}^{4}$ as $2^{2}$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$4 + 4 {(2^{\frac{1}{2}})}^{4} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 + 4 \cdot 2^{\frac{1}{2} \cdot 4} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Combine $\frac{1}{2}$ and $4$ .

$4 + 4 \cdot 2^{\frac{4}{2}} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4$ .

$4 + 4 \cdot 2^{\frac{2 \cdot 2}{2}} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factors.

Factor $2$ out of $2$ .

$4 + 4 \cdot 2^{\frac{2 \cdot 2}{2 (1)}} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor.

$4 + 4 \cdot 2^{\frac{2 \cdot 2}{2 \cdot 1}} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite the expression.

$4 + 4 \cdot 2^{\frac{2}{1}} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Divide $2$ by $1$ .

$4 + 4 \cdot 2^{2} i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Raise $2$ to the power of $2$ .

$4 + 4 \cdot 4 i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply $4$ by $4$ .

$4 + 16 i + 6 {\sqrt{2}}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$4 + 16 i + 6 {(2^{\frac{1}{2}})}^{2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 + 16 i + 6 \cdot 2^{\frac{1}{2} \cdot 2} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Combine $\frac{1}{2}$ and $2$ .

$4 + 16 i + 6 \cdot 2^{\frac{2}{2}} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 + 16 i + 6 \cdot 2^{\frac{2}{2}} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite the expression.

$4 + 16 i + 6 \cdot 2^{1} {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Evaluate the exponent.

$4 + 16 i + 6 \cdot 2 {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply $6$ by $2$ .

$4 + 16 i + 12 {(i \sqrt{2})}^{2} + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the product rule to $i \sqrt{2}$ .

$4 + 16 i + 12 (i^{2} {\sqrt{2}}^{2}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite $i^{2}$ as $- 1$ .

$4 + 16 i + 12 (- {\sqrt{2}}^{2}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$4 + 16 i + 12 (- {(2^{\frac{1}{2}})}^{2}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 + 16 i + 12 (- 2^{\frac{1}{2} \cdot 2}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Combine $\frac{1}{2}$ and $2$ .

$4 + 16 i + 12 (- 2^{\frac{2}{2}}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 + 16 i + 12 (- 2^{\frac{2}{2}}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Rewrite the expression.

$4 + 16 i + 12 (- 2^{1}) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Evaluate the exponent.

$4 + 16 i + 12 (- 1 \cdot 2) + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply $12 (- 1 \cdot 2)$ .

Multiply $- 1$ by $2$ .

$4 + 16 i + 12 \cdot - 2 + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Multiply $12$ by $- 2$ .

$4 + 16 i - 24 + 4 \sqrt{2} {(i \sqrt{2})}^{3} + {(i \sqrt{2})}^{4}$

Apply the product rule to $i \sqrt{2}$ .

$4 + 16 i - 24 + 4 \sqrt{2} (i^{3} {\sqrt{2}}^{3}) + {(i \sqrt{2})}^{4}$

Multiply $\sqrt{2}$ by ${\sqrt{2}}^{3}$ by adding the exponents.

Move ${\sqrt{2}}^{3}$ .

$4 + 16 i - 24 + 4 ({\sqrt{2}}^{3} \sqrt{2}) i^{3} + {(i \sqrt{2})}^{4}$

Multiply ${\sqrt{2}}^{3}$ by $\sqrt{2}$ .

Raise $\sqrt{2}$ to the power of $1$ .

$4 + 16 i - 24 + 4 ({\sqrt{2}}^{3} {\sqrt{2}}^{1}) i^{3} + {(i \sqrt{2})}^{4}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 + 16 i - 24 + 4 {\sqrt{2}}^{3 + 1} i^{3} + {(i \sqrt{2})}^{4}$

Add $3$ and $1$ .

$4 + 16 i - 24 + 4 {\sqrt{2}}^{4} i^{3} + {(i \sqrt{2})}^{4}$

Rewrite ${\sqrt{2}}^{4}$ as $2^{2}$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$4 + 16 i - 24 + 4 {(2^{\frac{1}{2}})}^{4} i^{3} + {(i \sqrt{2})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 + 16 i - 24 + 4 \cdot 2^{\frac{1}{2} \cdot 4} i^{3} + {(i \sqrt{2})}^{4}$

Combine $\frac{1}{2}$ and $4$ .

$4 + 16 i - 24 + 4 \cdot 2^{\frac{4}{2}} i^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4$ .

$4 + 16 i - 24 + 4 \cdot 2^{\frac{2 \cdot 2}{2}} i^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factors.

Factor $2$ out of $2$ .

$4 + 16 i - 24 + 4 \cdot 2^{\frac{2 \cdot 2}{2 (1)}} i^{3} + {(i \sqrt{2})}^{4}$

Cancel the common factor.

$4 + 16 i - 24 + 4 \cdot 2^{\frac{2 \cdot 2}{2 \cdot 1}} i^{3} + {(i \sqrt{2})}^{4}$

Rewrite the expression.

$4 + 16 i - 24 + 4 \cdot 2^{\frac{2}{1}} i^{3} + {(i \sqrt{2})}^{4}$

Divide $2$ by $1$ .

$4 + 16 i - 24 + 4 \cdot 2^{2} i^{3} + {(i \sqrt{2})}^{4}$

Raise $2$ to the power of $2$ .

$4 + 16 i - 24 + 4 \cdot 4 i^{3} + {(i \sqrt{2})}^{4}$

Multiply $4$ by $4$ .

$4 + 16 i - 24 + 16 i^{3} + {(i \sqrt{2})}^{4}$

Factor out $i^{2}$ .

$4 + 16 i - 24 + 16 (i^{2} \cdot i) + {(i \sqrt{2})}^{4}$

Rewrite $i^{2}$ as $- 1$ .

$4 + 16 i - 24 + 16 (- 1 \cdot i) + {(i \sqrt{2})}^{4}$

Rewrite $- 1 i$ as $- i$ .

$4 + 16 i - 24 + 16 (- i) + {(i \sqrt{2})}^{4}$

Multiply $- 1$ by $16$ .

$4 + 16 i - 24 - 16 i + {(i \sqrt{2})}^{4}$

Apply the product rule to $i \sqrt{2}$ .

$4 + 16 i - 24 - 16 i + i^{4} {\sqrt{2}}^{4}$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$4 + 16 i - 24 - 16 i + {(i^{2})}^{2} {\sqrt{2}}^{4}$

Rewrite $i^{2}$ as $- 1$ .

$4 + 16 i - 24 - 16 i + {(- 1)}^{2} {\sqrt{2}}^{4}$

Raise $- 1$ to the power of $2$ .

$4 + 16 i - 24 - 16 i + 1 {\sqrt{2}}^{4}$

Multiply ${\sqrt{2}}^{4}$ by $1$ .

$4 + 16 i - 24 - 16 i + {\sqrt{2}}^{4}$

Rewrite ${\sqrt{2}}^{4}$ as $2^{2}$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$4 + 16 i - 24 - 16 i + {(2^{\frac{1}{2}})}^{4}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 + 16 i - 24 - 16 i + 2^{\frac{1}{2} \cdot 4}$

Combine $\frac{1}{2}$ and $4$ .

$4 + 16 i - 24 - 16 i + 2^{\frac{4}{2}}$

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4$ .

$4 + 16 i - 24 - 16 i + 2^{\frac{2 \cdot 2}{2}}$

Cancel the common factors.

Factor $2$ out of $2$ .

$4 + 16 i - 24 - 16 i + 2^{\frac{2 \cdot 2}{2 (1)}}$

Cancel the common factor.

$4 + 16 i - 24 - 16 i + 2^{\frac{2 \cdot 2}{2 \cdot 1}}$

Rewrite the expression.

$4 + 16 i - 24 - 16 i + 2^{\frac{2}{1}}$

Divide $2$ by $1$ .

$4 + 16 i - 24 - 16 i + 2^{2}$

Raise $2$ to the power of $2$ .

$4 + 16 i - 24 - 16 i + 4$

Simplify by adding terms.

Subtract $24$ from $4$ .

$- 20 + 16 i - 16 i + 4$

Add $- 20$ and $4$ .

$- 16 + 16 i - 16 i$

Subtract $16 i$ from $16 i$ .

$- 16 + 0$

Add $- 16$ and $0$ .

$- 16$

Simplify (2(cos(pi/4)+isin(pi/4)))^4

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