Simplify (2(j^2)^4)/(-2j^5)

$\frac{2 {(j^{2})}^{4}}{- 2 j^{5}}$

Step 1

Cancel the common factor of $2$ and $- 2$ .

Factor $2$ out of $2 {(j^{2})}^{4}$ .

$\frac{2 ({(j^{2})}^{4})}{- 2 j^{5}}$

Cancel the common factors.

Factor $2$ out of $- 2 j^{5}$ .

$\frac{2 ({(j^{2})}^{4})}{2 (- j^{5})}$

Cancel the common factor.

$\frac{2 {(j^{2})}^{4}}{2 (- j^{5})}$

Rewrite the expression.

$\frac{{(j^{2})}^{4}}{- j^{5}}$

Step 2

Multiply the exponents in ${(j^{2})}^{4}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{j^{2 \cdot 4}}{- j^{5}}$

Multiply $2$ by $4$ .

$\frac{j^{8}}{- j^{5}}$

Step 3

Cancel the common factor of $j^{8}$ and $j^{5}$ .

Factor $j^{5}$ out of $j^{8}$ .

$\frac{j^{5} j^{3}}{- j^{5}}$

Move the negative one from the denominator of $\frac{j^{3}}{- 1}$ .

$- 1 \cdot j^{3}$

Step 4

Rewrite $- 1 \cdot j^{3}$ as $- j^{3}$ .

$- j^{3}$