Simplify (-27x^3(-x^7))/(16x^4)

$\frac{- 27 x^{3} (- x^{7})}{16 x^{4}}$

Step 1

Multiply $x^{3}$ by $x^{7}$ by adding the exponents.

Move $x^{7}$ .

$\frac{- 27 (x^{7} x^{3}) \cdot - 1}{16 x^{4}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{- 27 x^{7 + 3} \cdot - 1}{16 x^{4}}$

Add $7$ and $3$ .

$\frac{- 27 x^{10} \cdot - 1}{16 x^{4}}$

Step 2

Cancel the common factor of $x^{10}$ and $x^{4}$ .

Factor $x^{4}$ out of $- 27 x^{10} \cdot - 1$ .

$\frac{x^{4} (- 27 x^{6} \cdot - 1)}{16 x^{4}}$

Cancel the common factors.

Factor $x^{4}$ out of $16 x^{4}$ .

$\frac{x^{4} (- 27 x^{6} \cdot - 1)}{x^{4} \cdot 16}$

Cancel the common factor.

$\frac{x^{4} (- 27 x^{6} \cdot - 1)}{x^{4} \cdot 16}$

Rewrite the expression.

$\frac{- 27 x^{6} \cdot - 1}{16}$

Step 3

Multiply $- 1$ by $- 27$ .

$\frac{27 x^{6}}{16}$