Simplify (2a+1)/(3a)+5/4-(2a-3)/(6a^2)

$\frac{2 a + 1}{3 a} + \frac{5}{4} - \frac{2 a - 3}{6 a^{2}}$

Step 1

Find the common denominator.

Multiply $\frac{2 a + 1}{3 a}$ by $\frac{4 a}{4 a}$ .

$\frac{2 a + 1}{3 a} \cdot \frac{4 a}{4 a} + \frac{5}{4} - \frac{2 a - 3}{6 a^{2}}$

Multiply $\frac{2 a + 1}{3 a}$ by $\frac{4 a}{4 a}$ .

$\frac{(2 a + 1) (4 a)}{3 a (4 a)} + \frac{5}{4} - \frac{2 a - 3}{6 a^{2}}$

Multiply $\frac{5}{4}$ by $\frac{3 a^{2}}{3 a^{2}}$ .

$\frac{(2 a + 1) (4 a)}{3 a (4 a)} + \frac{5}{4} \cdot \frac{3 a^{2}}{3 a^{2}} - \frac{2 a - 3}{6 a^{2}}$

Multiply $\frac{5}{4}$ by $\frac{3 a^{2}}{3 a^{2}}$ .

$\frac{(2 a + 1) (4 a)}{3 a (4 a)} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{2 a - 3}{6 a^{2}}$

Multiply $\frac{2 a - 3}{6 a^{2}}$ by $\frac{2}{2}$ .

$\frac{(2 a + 1) (4 a)}{3 a (4 a)} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - (\frac{2 a - 3}{6 a^{2}} \cdot \frac{2}{2})$

Multiply $\frac{2 a - 3}{6 a^{2}}$ by $\frac{2}{2}$ .

$\frac{(2 a + 1) (4 a)}{3 a (4 a)} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Reorder the factors of $3 a (4 a)$ .

$\frac{(2 a + 1) (4 a)}{3 \cdot 4 a \cdot a} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Multiply $3$ by $4$ .

$\frac{(2 a + 1) (4 a)}{12 a \cdot a} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Raise $a$ to the power of $1$ .

$\frac{(2 a + 1) (4 a)}{12 (a^{1} a)} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Raise $a$ to the power of $1$ .

$\frac{(2 a + 1) (4 a)}{12 (a^{1} a^{1})} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{(2 a + 1) (4 a)}{12 a^{1 + 1}} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Add $1$ and $1$ .

$\frac{(2 a + 1) (4 a)}{12 a^{2}} + \frac{5 (3 a^{2})}{4 (3 a^{2})} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Reorder the factors of $4 (3 a^{2})$ .

$\frac{(2 a + 1) (4 a)}{12 a^{2}} + \frac{5 (3 a^{2})}{3 \cdot 4 a^{2}} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Multiply $3$ by $4$ .

$\frac{(2 a + 1) (4 a)}{12 a^{2}} + \frac{5 (3 a^{2})}{12 a^{2}} - \frac{(2 a - 3) \cdot 2}{6 a^{2} \cdot 2}$

Reorder the factors of $6 a^{2} \cdot 2$ .

$\frac{(2 a + 1) (4 a)}{12 a^{2}} + \frac{5 (3 a^{2})}{12 a^{2}} - \frac{(2 a - 3) \cdot 2}{2 \cdot 6 a^{2}}$

Multiply $2$ by $6$ .

$\frac{(2 a + 1) (4 a)}{12 a^{2}} + \frac{5 (3 a^{2})}{12 a^{2}} - \frac{(2 a - 3) \cdot 2}{12 a^{2}}$

Step 2

Combine the numerators over the common denominator.

$\frac{(2 a + 1) (4 a) + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Step 3

Simplify each term.

Apply the distributive property.

$\frac{2 a (4 a) + 1 (4 a) + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Rewrite using the commutative property of multiplication.

$\frac{2 \cdot 4 a \cdot a + 1 (4 a) + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Multiply $4 a$ by $1$ .

$\frac{2 \cdot 4 a \cdot a + 4 a + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Simplify each term.

Multiply $a$ by $a$ by adding the exponents.

Move $a$ .

$\frac{2 \cdot 4 (a \cdot a) + 4 a + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Multiply $a$ by $a$ .

$\frac{2 \cdot 4 a^{2} + 4 a + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Multiply $2$ by $4$ .

$\frac{8 a^{2} + 4 a + 5 (3 a^{2}) - (2 a - 3) \cdot 2}{12 a^{2}}$

Multiply $3$ by $5$ .

$\frac{8 a^{2} + 4 a + 15 a^{2} - (2 a - 3) \cdot 2}{12 a^{2}}$

Apply the distributive property.

$\frac{8 a^{2} + 4 a + 15 a^{2} + (- (2 a) - - 3) \cdot 2}{12 a^{2}}$

Multiply $2$ by $- 1$ .

$\frac{8 a^{2} + 4 a + 15 a^{2} + (- 2 a - - 3) \cdot 2}{12 a^{2}}$

Multiply $- 1$ by $- 3$ .

$\frac{8 a^{2} + 4 a + 15 a^{2} + (- 2 a + 3) \cdot 2}{12 a^{2}}$

Apply the distributive property.

$\frac{8 a^{2} + 4 a + 15 a^{2} - 2 a \cdot 2 + 3 \cdot 2}{12 a^{2}}$

Multiply $2$ by $- 2$ .

$\frac{8 a^{2} + 4 a + 15 a^{2} - 4 a + 3 \cdot 2}{12 a^{2}}$

Multiply $3$ by $2$ .

$\frac{8 a^{2} + 4 a + 15 a^{2} - 4 a + 6}{12 a^{2}}$

Step 4

Simplify by adding terms.

Combine the opposite terms in $8 a^{2} + 4 a + 15 a^{2} - 4 a + 6$ .

Subtract $4 a$ from $4 a$ .

$\frac{8 a^{2} + 15 a^{2} + 0 + 6}{12 a^{2}}$

Add $8 a^{2} + 15 a^{2}$ and $0$ .

$\frac{8 a^{2} + 15 a^{2} + 6}{12 a^{2}}$

Add $8 a^{2}$ and $15 a^{2}$ .

$\frac{23 a^{2} + 6}{12 a^{2}}$

Simplify (2a+1)/(3a)+5/4-(2a-3)/(6a^2)

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