Simplify ((2j^3p)^-1)/(10j^6)

$\frac{{(2 j^{3} p)}^{- 1}}{10 j^{6}}$

Move ${(2 j^{3} p)}^{- 1}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{10 j^{6} (2 j^{3} p)}$

Multiply $j^{6}$ by $j^{3}$ by adding the exponents.

Move $j^{3}$ .

$\frac{1}{10 (j^{3} j^{6}) (2 p)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{10 j^{3 + 6} (2 p)}$

Add $3$ and $6$ .

$\frac{1}{10 j^{9} (2 p)}$

Multiply $2$ by $10$ .

$\frac{1}{20 j^{9} p}$