Simplify (2tan(pi/8))/(1-tan(pi/8)^2)

$\frac{2 \tan (\frac{π}{8})}{1 - \tan^{2} (\frac{π}{8})}$

Step 1

The exact value of $\tan (\frac{π}{8})$ is $\sqrt{3 - 2 \sqrt{2}}$ .

Rewrite $\frac{π}{8}$ as an angle where the values of the six trigonometric functions are known divided by $2$ .

$\frac{2 \tan (\frac{\frac{π}{4}}{2})}{1 - \tan^{2} (\frac{π}{8})}$

Apply the tangent half-angle identity.

$\frac{2 (\pm \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}})}{1 - \tan^{2} (\frac{π}{8})}$

Change the $\pm$ to $+$ because tangent is positive in the first quadrant.

$\frac{2 \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}}{1 - \tan^{2} (\frac{π}{8})}$

Simplify $\sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}$ .

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}}{1 - \tan^{2} (\frac{π}{8})}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{\frac{\frac{2}{2} - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}}{1 - \tan^{2} (\frac{π}{8})}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}}{1 - \tan^{2} (\frac{π}{8})}$

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \frac{\sqrt{2}}{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2}{2} + \frac{\sqrt{2}}{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2 + \sqrt{2}}{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{2 \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Rewrite the expression.

$\frac{2 \sqrt{(2 - \sqrt{2}) \frac{1}{2 + \sqrt{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{(2 - \sqrt{2}) (\frac{1}{2 + \sqrt{2}} \cdot \frac{2 - \sqrt{2}}{2 - \sqrt{2}})}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{(2 + \sqrt{2}) (2 - \sqrt{2})}}}{1 - \tan^{2} (\frac{π}{8})}$

Expand the denominator using the FOIL method.

$\frac{2 \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{4 - 2 \sqrt{2} + \sqrt{2} \cdot 2 - {\sqrt{2}}^{2}}}}{1 - \tan^{2} (\frac{π}{8})}$

Simplify.

$\frac{2 \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Apply the distributive property.

$\frac{2 \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Rewrite the expression.

$\frac{2 \sqrt{2 - \sqrt{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Combine $\frac{2 - \sqrt{2}}{2}$ and $\sqrt{2}$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{(2 - \sqrt{2}) \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Simplify each term.

Apply the distributive property.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - \sqrt{2} \sqrt{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply $- \sqrt{2} \sqrt{2}$ .

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} \sqrt{2})}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} {\sqrt{2}}^{1})}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{1 + 1}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Add $1$ and $1$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Simplify each term.

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {(2^{\frac{1}{2}})}^{2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{1}{2} \cdot 2}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Rewrite the expression.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{1}}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Evaluate the exponent.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 1 \cdot 2}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply $- 1$ by $2$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factor of $2 \sqrt{2} - 2$ and $2$ .

Factor $2$ out of $2 \sqrt{2}$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) - 2}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Factor $2$ out of $- 2$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) + 2 \cdot - 1}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Factor $2$ out of $2 (\sqrt{2}) + 2 (- 1)$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 (1)}}}{1 - \tan^{2} (\frac{π}{8})}$

Cancel the common factor.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 \cdot 1}}}{1 - \tan^{2} (\frac{π}{8})}$

Rewrite the expression.

$\frac{2 \sqrt{2 - \sqrt{2} - \frac{\sqrt{2} - 1}{1}}}{1 - \tan^{2} (\frac{π}{8})}$

Divide $\sqrt{2} - 1$ by $1$ .

$\frac{2 \sqrt{2 - \sqrt{2} - (\sqrt{2} - 1)}}{1 - \tan^{2} (\frac{π}{8})}$

Apply the distributive property.

$\frac{2 \sqrt{2 - \sqrt{2} - \sqrt{2} - - 1}}{1 - \tan^{2} (\frac{π}{8})}$

Multiply $- 1$ by $- 1$ .

$\frac{2 \sqrt{2 - \sqrt{2} - \sqrt{2} + 1}}{1 - \tan^{2} (\frac{π}{8})}$

Add $2$ and $1$ .

$\frac{2 \sqrt{3 - \sqrt{2} - \sqrt{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Subtract $\sqrt{2}$ from $- \sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \tan^{2} (\frac{π}{8})}$

Step 2

Simplify the denominator.

Rewrite $1$ as $1^{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1^{2} - \tan^{2} (\frac{π}{8})}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = \tan (\frac{π}{8})$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \tan (\frac{π}{8})) (1 - \tan (\frac{π}{8}))}$

Simplify.

The exact value of $\tan (\frac{π}{8})$ is $\sqrt{3 - 2 \sqrt{2}}$ .

Rewrite $\frac{π}{8}$ as an angle where the values of the six trigonometric functions are known divided by $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \tan (\frac{\frac{π}{4}}{2})) (1 - \tan (\frac{π}{8}))}$

Apply the tangent half-angle identity.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 \pm \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}) (1 - \tan (\frac{π}{8}))}$

Change the $\pm$ to $+$ because tangent is positive in the first quadrant.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}) (1 - \tan (\frac{π}{8}))}$

Simplify $\sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}$ .

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}) (1 - \tan (\frac{π}{8}))}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{\frac{2}{2} - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}) (1 - \tan (\frac{π}{8}))}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}}) (1 - \tan (\frac{π}{8}))}$

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \frac{\sqrt{2}}{2}}}) (1 - \tan (\frac{π}{8}))}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2}{2} + \frac{\sqrt{2}}{2}}}) (1 - \tan (\frac{π}{8}))}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2 + \sqrt{2}}{2}}}) (1 - \tan (\frac{π}{8}))}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}}) (1 - \tan (\frac{π}{8}))}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{(2 - \sqrt{2}) \frac{1}{2 + \sqrt{2}}}) (1 - \tan (\frac{π}{8}))}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{(2 - \sqrt{2}) (\frac{1}{2 + \sqrt{2}} \cdot \frac{2 - \sqrt{2}}{2 - \sqrt{2}})}) (1 - \tan (\frac{π}{8}))}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{(2 + \sqrt{2}) (2 - \sqrt{2})}}) (1 - \tan (\frac{π}{8}))}$

Expand the denominator using the FOIL method.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{4 - 2 \sqrt{2} + \sqrt{2} \cdot 2 - {\sqrt{2}}^{2}}}) (1 - \tan (\frac{π}{8}))}$

Simplify.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Combine $\frac{2 - \sqrt{2}}{2}$ and $\sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{(2 - \sqrt{2}) \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Simplify each term.

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - \sqrt{2} \sqrt{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Multiply $- \sqrt{2} \sqrt{2}$ .

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} \sqrt{2})}{2}}) (1 - \tan (\frac{π}{8}))}$

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} {\sqrt{2}}^{1})}{2}}) (1 - \tan (\frac{π}{8}))}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{1 + 1}}{2}}) (1 - \tan (\frac{π}{8}))}$

Add $1$ and $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Simplify each term.

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {(2^{\frac{1}{2}})}^{2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{1}{2} \cdot 2}}{2}}) (1 - \tan (\frac{π}{8}))}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}}) (1 - \tan (\frac{π}{8}))}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{1}}{2}}) (1 - \tan (\frac{π}{8}))}$

Evaluate the exponent.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 1 \cdot 2}{2}}) (1 - \tan (\frac{π}{8}))}$

Multiply $- 1$ by $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2}{2}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factor of $2 \sqrt{2} - 2$ and $2$ .

Factor $2$ out of $2 \sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) - 2}{2}}) (1 - \tan (\frac{π}{8}))}$

Factor $2$ out of $- 2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) + 2 \cdot - 1}{2}}) (1 - \tan (\frac{π}{8}))}$

Factor $2$ out of $2 (\sqrt{2}) + 2 (- 1)$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 (1)}}) (1 - \tan (\frac{π}{8}))}$

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 \cdot 1}}) (1 - \tan (\frac{π}{8}))}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \frac{\sqrt{2} - 1}{1}}) (1 - \tan (\frac{π}{8}))}$

Divide $\sqrt{2} - 1$ by $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - (\sqrt{2} - 1)}) (1 - \tan (\frac{π}{8}))}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \sqrt{2} - - 1}) (1 - \tan (\frac{π}{8}))}$

Multiply $- 1$ by $- 1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{2 - \sqrt{2} - \sqrt{2} + 1}) (1 - \tan (\frac{π}{8}))}$

Add $2$ and $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - \sqrt{2} - \sqrt{2}}) (1 - \tan (\frac{π}{8}))}$

Subtract $\sqrt{2}$ from $- \sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \tan (\frac{π}{8}))}$

The exact value of $\tan (\frac{π}{8})$ is $\sqrt{3 - 2 \sqrt{2}}$ .

Rewrite $\frac{π}{8}$ as an angle where the values of the six trigonometric functions are known divided by $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \tan (\frac{\frac{π}{4}}{2}))}$

Apply the tangent half-angle identity.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - (\pm \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}))}$

Change the $\pm$ to $+$ because tangent is positive in the first quadrant.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}})}$

Simplify $\sqrt{\frac{1 - \cos (\frac{π}{4})}{1 + \cos (\frac{π}{4})}}$ .

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}})}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{\frac{2}{2} - \frac{\sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}})}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \cos (\frac{π}{4})}})}$

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{1 + \frac{\sqrt{2}}{2}}})}$

Write $1$ as a fraction with a common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2}{2} + \frac{\sqrt{2}}{2}}})}$

Combine the numerators over the common denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{\frac{2 - \sqrt{2}}{2}}{\frac{2 + \sqrt{2}}{2}}})}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{\frac{2 - \sqrt{2}}{2} \cdot \frac{2}{2 + \sqrt{2}}})}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{(2 - \sqrt{2}) \frac{1}{2 + \sqrt{2}}})}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{(2 - \sqrt{2}) (\frac{1}{2 + \sqrt{2}} \cdot \frac{2 - \sqrt{2}}{2 - \sqrt{2}})})}$

Multiply $\frac{1}{2 + \sqrt{2}}$ by $\frac{2 - \sqrt{2}}{2 - \sqrt{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{(2 + \sqrt{2}) (2 - \sqrt{2})}})}$

Expand the denominator using the FOIL method.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{4 - 2 \sqrt{2} + \sqrt{2} \cdot 2 - {\sqrt{2}}^{2}}})}$

Simplify.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{(2 - \sqrt{2}) \frac{2 - \sqrt{2}}{2}})}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 \frac{2 - \sqrt{2}}{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}})}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \sqrt{2} \frac{2 - \sqrt{2}}{2}})}$

Combine $\frac{2 - \sqrt{2}}{2}$ and $\sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{(2 - \sqrt{2}) \sqrt{2}}{2}})}$

Simplify each term.

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - \sqrt{2} \sqrt{2}}{2}})}$

Multiply $- \sqrt{2} \sqrt{2}$ .

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} \sqrt{2})}{2}})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - ({\sqrt{2}}^{1} {\sqrt{2}}^{1})}{2}})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{1 + 1}}{2}})}$

Add $1$ and $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {\sqrt{2}}^{2}}{2}})}$

Simplify each term.

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - {(2^{\frac{1}{2}})}^{2}}{2}})}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{1}{2} \cdot 2}}{2}})}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{\frac{2}{2}}}{2}})}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2^{1}}{2}})}$

Evaluate the exponent.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 1 \cdot 2}{2}})}$

Multiply $- 1$ by $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 \sqrt{2} - 2}{2}})}$

Cancel the common factor of $2 \sqrt{2} - 2$ and $2$ .

Factor $2$ out of $2 \sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) - 2}{2}})}$

Factor $2$ out of $- 2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2}) + 2 \cdot - 1}{2}})}$

Factor $2$ out of $2 (\sqrt{2}) + 2 (- 1)$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2}})}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 (1)}})}$

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{2 (\sqrt{2} - 1)}{2 \cdot 1}})}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \frac{\sqrt{2} - 1}{1}})}$

Divide $\sqrt{2} - 1$ by $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - (\sqrt{2} - 1)})}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \sqrt{2} - - 1})}$

Multiply $- 1$ by $- 1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{2 - \sqrt{2} - \sqrt{2} + 1})}$

Add $2$ and $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{3 - \sqrt{2} - \sqrt{2}})}$

Subtract $\sqrt{2}$ from $- \sqrt{2}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{3 - 2 \sqrt{2}})}$

Step 3

Expand $(1 + \sqrt{3 - 2 \sqrt{2}}) (1 - \sqrt{3 - 2 \sqrt{2}})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 (1 - \sqrt{3 - 2 \sqrt{2}}) + \sqrt{3 - 2 \sqrt{2}} (1 - \sqrt{3 - 2 \sqrt{2}})}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 \cdot 1 + 1 (- \sqrt{3 - 2 \sqrt{2}}) + \sqrt{3 - 2 \sqrt{2}} (1 - \sqrt{3 - 2 \sqrt{2}})}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 \cdot 1 + 1 (- \sqrt{3 - 2 \sqrt{2}}) + \sqrt{3 - 2 \sqrt{2}} \cdot 1 + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{3 - 2 \sqrt{2}})}$

Step 4

Simplify and combine like terms.

Simplify each term.

Multiply $1$ by $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 + 1 (- \sqrt{3 - 2 \sqrt{2}}) + \sqrt{3 - 2 \sqrt{2}} \cdot 1 + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{3 - 2 \sqrt{2}})}$

Multiply $- \sqrt{3 - 2 \sqrt{2}}$ by $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} \cdot 1 + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{3 - 2 \sqrt{2}})}$

Multiply $\sqrt{3 - 2 \sqrt{2}}$ by $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{3 - 2 \sqrt{2}})}$

Multiply $\sqrt{3 - 2 \sqrt{2}} (- \sqrt{3 - 2 \sqrt{2}})$ .

Raise $\sqrt{3 - 2 \sqrt{2}}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - ({\sqrt{3 - 2 \sqrt{2}}}^{1} \sqrt{3 - 2 \sqrt{2}})}$

Raise $\sqrt{3 - 2 \sqrt{2}}$ to the power of $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - ({\sqrt{3 - 2 \sqrt{2}}}^{1} {\sqrt{3 - 2 \sqrt{2}}}^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {\sqrt{3 - 2 \sqrt{2}}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {\sqrt{3 - 2 \sqrt{2}}}^{2}}$

Rewrite ${\sqrt{3 - 2 \sqrt{2}}}^{2}$ as $3 - 2 \sqrt{2}$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3 - 2 \sqrt{2}}$ as ${(3 - 2 \sqrt{2})}^{\frac{1}{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {({(3 - 2 \sqrt{2})}^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {(3 - 2 \sqrt{2})}^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {(3 - 2 \sqrt{2})}^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {(3 - 2 \sqrt{2})}^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - {(3 - 2 \sqrt{2})}^{1}}$

Simplify.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - (3 - 2 \sqrt{2})}$

Apply the distributive property.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - 1 \cdot 3 - (- 2 \sqrt{2})}$

Multiply $- 1$ by $3$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - 3 - (- 2 \sqrt{2})}$

Multiply $- 2$ by $- 1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{1 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} - 3 + 2 \sqrt{2}}$

Subtract $3$ from $1$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{- 2 - \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} + 2 \sqrt{2}}$

Add $- \sqrt{3 - 2 \sqrt{2}}$ and $\sqrt{3 - 2 \sqrt{2}}$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{- 2 + 0 + 2 \sqrt{2}}$

Add $- 2$ and $0$ .

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{- 2 + 2 \sqrt{2}}$

Step 5

Cancel the common factor of $2$ and $- 2 + 2 \sqrt{2}$ .

Factor $2$ out of $2 \sqrt{3 - 2 \sqrt{2}}$ .

$\frac{2 (\sqrt{3 - 2 \sqrt{2}})}{- 2 + 2 \sqrt{2}}$

Cancel the common factors.

Factor $2$ out of $- 2$ .

$\frac{2 (\sqrt{3 - 2 \sqrt{2}})}{2 \cdot - 1 + 2 \sqrt{2}}$

Factor $2$ out of $2 \sqrt{2}$ .

$\frac{2 (\sqrt{3 - 2 \sqrt{2}})}{2 \cdot - 1 + 2 (\sqrt{2})}$

Factor $2$ out of $2 \cdot - 1 + 2 (\sqrt{2})$ .

$\frac{2 (\sqrt{3 - 2 \sqrt{2}})}{2 \cdot (- 1 + \sqrt{2})}$

Cancel the common factor.

$\frac{2 \sqrt{3 - 2 \sqrt{2}}}{2 \cdot (- 1 + \sqrt{2})}$

Rewrite the expression.

$\frac{\sqrt{3 - 2 \sqrt{2}}}{- 1 + \sqrt{2}}$

Step 6

Multiply $\frac{\sqrt{3 - 2 \sqrt{2}}}{- 1 + \sqrt{2}}$ by $\frac{- 1 - \sqrt{2}}{- 1 - \sqrt{2}}$ .

$\frac{\sqrt{3 - 2 \sqrt{2}}}{- 1 + \sqrt{2}} \cdot \frac{- 1 - \sqrt{2}}{- 1 - \sqrt{2}}$

Step 7

Simplify terms.

Multiply $\frac{\sqrt{3 - 2 \sqrt{2}}}{- 1 + \sqrt{2}}$ by $\frac{- 1 - \sqrt{2}}{- 1 - \sqrt{2}}$ .

$\frac{\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2})}{(- 1 + \sqrt{2}) (- 1 - \sqrt{2})}$

Expand the denominator using the FOIL method.

$\frac{\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2})}{1 + \sqrt{2} + \sqrt{2} \cdot - 1 - {\sqrt{2}}^{2}}$

Simplify.

$\frac{\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2})}{- 1}$

Simplify the expression.

Move the negative one from the denominator of $\frac{\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2})}{- 1}$ .

$- 1 \cdot (\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2}))$

Rewrite $- 1 \cdot (\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2}))$ as $- (\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2}))$ .

$- (\sqrt{3 - 2 \sqrt{2}} (- 1 - \sqrt{2}))$

Apply the distributive property.

$- (\sqrt{3 - 2 \sqrt{2}} \cdot - 1 + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{2}))$

Move $- 1$ to the left of $\sqrt{3 - 2 \sqrt{2}}$ .

$- (- 1 \cdot \sqrt{3 - 2 \sqrt{2}} + \sqrt{3 - 2 \sqrt{2}} (- \sqrt{2}))$

Combine using the product rule for radicals.

$- (- 1 \cdot \sqrt{3 - 2 \sqrt{2}} - \sqrt{(3 - 2 \sqrt{2}) \cdot 2})$

Step 8

Rewrite $- 1 \sqrt{3 - 2 \sqrt{2}}$ as $- \sqrt{3 - 2 \sqrt{2}}$ .

$- (- \sqrt{3 - 2 \sqrt{2}} - \sqrt{(3 - 2 \sqrt{2}) \cdot 2})$

Step 9

Apply the distributive property.

$- - \sqrt{3 - 2 \sqrt{2}} - - \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Step 10

Multiply $- - \sqrt{3 - 2 \sqrt{2}}$ .

Multiply $- 1$ by $- 1$ .

$1 \sqrt{3 - 2 \sqrt{2}} - - \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Multiply $\sqrt{3 - 2 \sqrt{2}}$ by $1$ .

$\sqrt{3 - 2 \sqrt{2}} - - \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Step 11

Multiply $- - \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$ .

Multiply $- 1$ by $- 1$ .

$\sqrt{3 - 2 \sqrt{2}} + 1 \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Multiply $\sqrt{(3 - 2 \sqrt{2}) \cdot 2}$ by $1$ .

$\sqrt{3 - 2 \sqrt{2}} + \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Step 12

The result can be shown in multiple forms.

Exact Form:

$\sqrt{3 - 2 \sqrt{2}} + \sqrt{(3 - 2 \sqrt{2}) \cdot 2}$

Decimal Form:

$1.000000000000 \dots$

Simplify (2tan(pi/8))/(1-tan(pi/8)^2)

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