Simplify (2x^2+6x-20)/(2x-4)

$\frac{2 x^{2} + 6 x - 20}{2 x - 4}$

Cancel the common factor of $2 x^{2} + 6 x - 20$ and $2 x - 4$ .

Factor $2$ out of $2 x^{2}$ .

$\frac{2 (x^{2}) + 6 x - 20}{2 x - 4}$

Factor $2$ out of $6 x$ .

$\frac{2 (x^{2}) + 2 (3 x) - 20}{2 x - 4}$

Factor $2$ out of $2 (x^{2}) + 2 (3 x)$ .

$\frac{2 (x^{2} + 3 x) - 20}{2 x - 4}$

Factor $2$ out of $- 20$ .

$\frac{2 (x^{2} + 3 x) + 2 \cdot - 10}{2 x - 4}$

Factor $2$ out of $2 (x^{2} + 3 x) + 2 (- 10)$ .

$\frac{2 (x^{2} + 3 x - 10)}{2 x - 4}$

Cancel the common factors.

Factor $2$ out of $2 x$ .

$\frac{2 (x^{2} + 3 x - 10)}{2 (x) - 4}$

Factor $2$ out of $- 4$ .

$\frac{2 (x^{2} + 3 x - 10)}{2 x + 2 \cdot - 2}$

Factor $2$ out of $2 x + 2 \cdot - 2$ .

$\frac{2 (x^{2} + 3 x - 10)}{2 (x - 2)}$

Cancel the common factor.

$\frac{2 (x^{2} + 3 x - 10)}{2 (x - 2)}$

Rewrite the expression.

$\frac{x^{2} + 3 x - 10}{x - 2}$

Factor $x^{2} + 3 x - 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 10$ and whose sum is $3$ .

$- 2, 5$

Write the factored form using these integers.

$\frac{(x - 2) (x + 5)}{x - 2}$

Cancel the common factor of $x - 2$ .

Cancel the common factor.

$\frac{(x - 2) (x + 5)}{x - 2}$

Divide $x + 5$ by $1$ .

$x + 5$

Simplify (2x^2+6x-20)/(2x-4)

Related Questions

Support LCMGCF.com by disabling your adblocker.