Simplify ((2x)/(x-3))^2+3

${(\frac{2 x}{x - 3})}^{2} + 3$

Step 1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $\frac{2 x}{x - 3}$ .

$\frac{{(2 x)}^{2}}{{(x - 3)}^{2}} + 3$

Apply the product rule to $2 x$ .

$\frac{2^{2} x^{2}}{{(x - 3)}^{2}} + 3$

Step 2

Raise $2$ to the power of $2$ .

$\frac{4 x^{2}}{{(x - 3)}^{2}} + 3$